515. Find Largest Value in Each Tree Row

My BFS solution:

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public List<Integer> largestValues(TreeNode root) {
        List<Integer> res = new ArrayList<>();
        if(root==null)
            return res;
        Queue<TreeNode> queue = new LinkedList<>();
        queue.offer(root);
        while(!queue.isEmpty()){
            int size = queue.size();
            int max = Integer.MIN_VALUE;
            for(int i=0;i<size;i++){
                TreeNode node = queue.poll();
                max = Math.max(max, node.val);
                if(node.left!=null)
                    queue.offer(node.left);
                if(node.right!=null)
                    queue.offer(node.right);
            }
            res.add(max);
        }
        return res;
    }
}

标签：right,TreeNode,val,int,Tree,Value,queue,Largest,left
来源： https://www.cnblogs.com/feiflytech/p/16133324.html