226. 翻转二叉树
作者:互联网
难度:简单
题目描述:
给你一棵二叉树的根节点 root ,翻转这棵二叉树,并返回其根节点。
示例 1:
输入:root = [4,2,7,1,3,6,9]
输出:[4,7,2,9,6,3,1]
示例 2:
输入:root = [2,1,3]
输出:[2,3,1]
示例 3:
输入:root = []
输出:[]
解题思路:递归
Java程序:
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public TreeNode invertTree(TreeNode root) {
if(root == null){
return root;
}
TreeNode left = invertTree(root.right);
TreeNode right = invertTree(root.left);
root.right = right;
root.left = left;
return root;
}
}
标签:right,TreeNode,val,示例,二叉树,226,left,root,翻转 来源: https://blog.csdn.net/LIsaWinLee/article/details/123635846