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226. 翻转二叉树

作者:互联网

难度:简单

题目描述:

给你一棵二叉树的根节点 root ,翻转这棵二叉树,并返回其根节点。

示例 1:

在这里插入图片描述

输入:root = [4,2,7,1,3,6,9]
输出:[4,7,2,9,6,3,1]
示例 2:

在这里插入图片描述

输入:root = [2,1,3]
输出:[2,3,1]
示例 3:

输入:root = []
输出:[]

解题思路:递归

Java程序:

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public TreeNode invertTree(TreeNode root) {
        if(root == null){
            return root;
        }
        TreeNode left = invertTree(root.right);
        TreeNode right = invertTree(root.left);
        root.right = right;
        root.left = left;
        return root;
    }
}

标签:right,TreeNode,val,示例,二叉树,226,left,root,翻转
来源: https://blog.csdn.net/LIsaWinLee/article/details/123635846