【墨鳌】【234.回文链表】

解题思路

• 精彩 O(1)

class Solution {
public:
    bool isPalindrome(ListNode* head) {
        if (head == nullptr) {
            return true;
        }
        
        ListNode* firstHalfEnd = endOfFirstHalf(head);
        ListNode* secondHalfStart = reverseList(firstHalfEnd->next);

        ListNode* p1 = head;
        ListNode* p2 = secondHalfStart;
        bool result = true;
        while (result && p2 != nullptr) {
            if (p1->val != p2->val) {
                result = false;
            }
            p1 = p1->next;
            p2 = p2->next;
        }
        
        firstHalfEnd->next = reverseList(secondHalfStart);
        return result;
    }

    ListNode* reverseList(ListNode* head) {
        ListNode* prev = nullptr;
        ListNode* curr = head;
        while (curr != nullptr) {
            ListNode* nextTemp = curr->next;
            curr->next = prev;
            prev = curr;
            curr = nextTemp;
        }
        return prev;
    }

    ListNode* endOfFirstHalf(ListNode* head) {
        ListNode* fast = head;
        ListNode* slow = head;
        while (fast->next != nullptr && fast->next->next != nullptr) {
            fast = fast->next->next;
            slow = slow->next;
        }
        return slow;
    }
};

标签：head,ListNode,nullptr,fast,next,链表,墨鳌,234,curr
来源： https://www.cnblogs.com/JasonCow/p/15982115.html