将list集合,元素随机打乱
作者:互联网
1:for循环+随机数 实现相同位置的元素交换
public <T> void shuffle(List<T> list) { int size = list.size(); Random random = new Random(); for(int i = 0; i < size; i++) { int randomPos = random.nextInt(size); T temp = list.get(i); list.set(i, list.get(randomPos)); list.set(randomPos, temp); } }
2:Collections.swap实现
public <T> void shuffle(List<T> list) { int size = list.size(); Random random = new Random(); for(int i = 0; i < size; i++) { int randomPos = random.nextInt(size); Collections.swap(list, i, randomPos); } }
3:Collections.shuffle实现
public <T> void shuffle(List<T> list){ Collections.shuffle(list); }
标签:shuffle,int,打乱,random,list,随机,randomPos,size 来源: https://www.cnblogs.com/jelly12345/p/15908804.html