C语言计算用户输入的句子的个数

#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[]) {
//返回值为sentence的个数 
int count(char str[],int num);
	char str[100];
	int i,num=0;
	//input 
	printf("please input your sentences:\n");
	printf("（please input 0 if you have finished）\n");
	for(i=0;i<100;i++){
	    str[i]=getchar();
		if(str[i]=='0')
		{
		    break;
		}
		else{
			num++;
		}
	}
	//printf("num=%d",num);
	printf("The number of sentences you entered is %d.\n",count(str,num));
	system ("pause");
	return 0;
}
int count(char str[],int num){
	int i;	
	int count=0;
	for(i=0;i<num;i++){
		if(str[i]=='?'||str[i]=='!'||str[i]=='.')
		{
			count++;	
		}
	 }
 return (count);
}

标签：int,please,个数,C语言,char,num,printf,input,句子
来源： https://blog.csdn.net/m0_62796003/article/details/122855293