其他分享
首页 > 其他分享> > Acwing 1096. 地牢大师(三维BFS)

Acwing 1096. 地牢大师(三维BFS)

作者:互联网

三维BFS啦~之前没见过,长长见识,注意三维的偏移量的标法 

#include <cstdio>
#include <cstring>
#include <iostream>
#include<queue>
#include <algorithm>
using namespace std;
struct node
{
	int x,y,z;
	int d;
};
const int N = 105;
int n,m,h;
char g[N][N][N];
bool vis[N][N][N];
int dx[]={0,1,0,-1,0,0};
int dy[]={1,0,-1,0,0,0};
int dz[]={0,0,0,0,1,-1};
int x1,y1,z1,x2,y2,z2;
int bfs()
{
	queue<node> q;
	q.push({x1,y1,z1,0});
	memset(vis,false,sizeof vis);
	vis[z1][x1][y1]=true;
	while(!q.empty())
	{
		node t=q.front();q.pop();
		int x=t.x,y=t.y,z=t.z,d=t.d;
		if(x==x2&&y==y2&&z==z2) return d;
		for(int i=0;i<6;i++)
		{
			int nx=x+dx[i],ny=y+dy[i],nz=z+dz[i];
			if(nx<1||nx>n||ny<1||ny>m||nz<1||nz>h) continue;
			if(g[nz][nx][ny]=='#') continue;
			if(vis[nz][nx][ny]) continue;
			vis[nz][nx][ny]=true;
			q.push({nx,ny,nz,d+1});
		}	
	}
	return -1;
}

int main()
{
	while(cin>>h>>n>>m&&h&&n&&m)
	{
		for(int i=1;i<=h;i++)
			for(int j=1;j<=n;j++)
				cin>>g[i][j]+1;
		for(int i=1;i<=h;i++)
			for(int j=1;j<=n;j++)
				for(int z=1;z<=m;z++)
					if(g[i][j][z]=='S')
					{
						z1=i;x1=j;y1=z;
					}
					else if(g[i][j][z]=='E')
					{
						z2=i;x2=j;y2=z;
					}
		int res=bfs();
		if(res==-1) cout<<"Trapped!"<<endl;
		else cout<<"Escaped in "<<res<<" minute(s)."<<endl;
	}
}

 

 

标签:1096,ny,int,BFS,vis,nz,&&,include,Acwing
来源: https://blog.csdn.net/weixin_50533561/article/details/122791213