556. Next Greater Element III

This is the similar problem with "31. Next Permutation", the differences are:

1. 31 don't care about whether the "next" is larger or not, but 556 care, 556 need the next is larger than it.

2. 31's input is an array, while 556 is a number.

3. for 556, If the result is larger than Integer.MAX_VALUE, return -1.

The solution is as following:

    public int nextGreaterElement(int n) {
        char[] cs = (n + "").toCharArray();  //1. convert number to an array!
        int index = 0;
        for (int i = cs.length - 1; i > 0; i--) {
            if (cs[i] > cs[i - 1]) {
                index = i;
                break;
            }
        }
        if (index == 0)     //2. the next must be larger than the original, for example, 4321's next is 1234, should return -1.
            return -1;

        for (int i = cs.length - 1; i >= index; i--) {
            if (cs[i] > cs[index - 1]) {
                swap(cs, i, index - 1);
                break;
            }
        }

        reverse(cs, index);
        long temp = Long.valueOf(new String(cs));  //3. the result might be larger than Integer
        return temp > Integer.MAX_VALUE ? -1 : (int) temp;
    }

    private void swap(char[] cs, int i, int j) {
        char temp = cs[i];
        cs[i] = cs[j];
        cs[j] = temp;
    }

    private void reverse(char[] cs, int start) {
        int i = start, j = cs.length - 1;
        while (i < j) {
            swap(cs, i, j);
            i++;
            j--;
        }
    }

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来源： https://www.cnblogs.com/feiflytech/p/15861167.html