LeetCode.107. 二叉树的层序遍历 II
作者:互联网
BFS
这道题与102层序遍历几乎一致,唯一不同的就是输出的ansList,本题是从底层到上层的,代码中的区别为,在将每层的遍历结果levelList加入ansList时,自顶向下的层序遍历时每次添加在尾部,而本题的方法时添加在头部;
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public List<List<Integer>> levelOrderBottom(TreeNode root) {
// 利用链表来实现在链表头添加元素,实现自底向上的层序遍历
List<List<Integer>> ansList = new LinkedList<>();
Queue<TreeNode> queue = new LinkedList<>();
if (root == null) {
return ansList;
}
queue.offer(root);
while (!queue.isEmpty()) {
List<Integer> levelList = new ArrayList<>();
int size = queue.size();
for (int i = 0; i < size; i++) {
TreeNode tmpNode = queue.poll();
levelList.add(tmpNode.val);
if (tmpNode.left != null) {
queue.offer(tmpNode.left);
}
if (tmpNode.right != null) {
queue.offer(tmpNode.right);
}
}
// 在链表位置0加入levelList
ansList.add(0, levelList);
}
return ansList;
}
}
复杂度分析:
- 时间复杂度:O(n)
- 空间复杂度:O(n)
标签:right,TreeNode,val,层序,queue,二叉树,LeetCode.107,ansList,tmpNode 来源: https://blog.csdn.net/weixin_45867071/article/details/122748147