输入日期，获得该日期往后一个月同一天，连续获得多个月

def getNextDates(year,month,day,times):
    dateList = []
    for i in range(times):
        tmpYear = year + (month+i)//12
        tmpMonth = (month+i) % 12+1
        tmpDay = day
        try:
            dateList.append(datetime.date(tmpYear,tmpMonth,tmpDay))
        except:
            if tmpMonth == 12:
                dateList.append(datetime.date(tmpYear+1, 1, tmpDay))
            else:
                dateList.append(datetime.date(tmpYear, tmpMonth + 1, 1))
    return dateList



if __name__ == "__main__":
    print(getNextDates(2008,3,30,12))

执行结果

[datetime.date(2008, 4, 30), datetime.date(2008, 5, 30), datetime.date(2008, 6, 30), datetime.date(2008, 7, 30), datetime.date(2008, 8, 30), datetime.date(2008, 9, 30), datetime.date(2008, 10, 30), datetime.date(2008, 11, 30), datetime.date(2008, 12, 30), datetime.date(2009, 1, 30), datetime.date(2009, 3, 1), datetime.date(2009, 3, 30)]

相对获取单个结果，主要区别在于循环获取并处理年份和月份上，年份需要+月份除以12的整数部分，月份为循环获得月份除以12获得余数上面

标签：12,同一天,30,dateList,datetime,获得,日期,date,2008
来源： https://blog.csdn.net/wwenww/article/details/122722025