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MATLAB求带符号的矩阵的逆

作者:互联网

syms a
syms b
B=[-sin(a) -sin(b)*cos(a) cos(b)*cos(a);cos(a) -sin(b)*sin(a),cos(b)*sin(a);0 cos(b) sin(b)];
inv(B)
inv(B)*B;

检查是否是正确的,只需把syms代入具体的值:

a=pi/2
b=pi/3
B=[-sin(a) -sin(b)*cos(a) cos(b)*cos(a);cos(a) -sin(b)*sin(a),cos(b)*sin(a);0 cos(b) sin(b)];
inv(B)
inv(B)*B

标签:cos,带符号,inv,矩阵,syms,MATLAB,pi,sin
来源: https://blog.csdn.net/qq_42928559/article/details/122683464