PAT 1011 A+B和C

#include <iostream>
#include <cmath>


using namespace std;
 

int main()
{
    int n;
    cin>>n;
    double a,b,c;
    
    string t[100000];
    int count=0;
    
    for(int i=0;i<n;i++)
     {
     	 cin>>a>>b>>c;
     	 double res = a+b;
     	 if(res>c)
     	 {
     	 	t[count] = "true"; count++;
		 }
		 else{
		 	t[count] = "false"; count++;
		 }
	 } 
	 
	 for(int i=0;i<count;i++)
	 {
	 	if(i==(count-1))
	 	{
	 		cout<<"Case #"<<i+1<<": "<<t[i];
	 		break;	
		 }
	 	cout<<"Case #"<<i+1<<": "<<t[i]<<endl;
	 }
	 
	 
	 
	 
	 
	 
	    
}

标签：count,PAT,int,double,++,res,include,1011
来源： https://blog.csdn.net/hehe_www2012/article/details/122567748