模拟散列表开放寻址法
作者:互联网
#include <iostream>
#include <cstring>
using namespace std;
const int N=200003,null=0x3f3f3f3f;
int h[N];
bool find1(int x){
int k=(x%N+N)%N;
while(h[k]!=null && h[k]!=x){
k++;
if(k==N) k=0;
}
return k;
}
int main()
{
int n;
scanf("%d",&n);
memset(h,0x3f,sizeof h);
while(n--){
char op[2];
int x;
scanf("%s%d",op,&x);
int k=find1(x);
if(*op == 'I')h[k]=x;
else{
if(h[k]!=null) puts("Yes");
else puts("No");
}
}
return 0;
}
标签:puts,int,scanf,find1,列表,寻址,null,模拟,op 来源: https://blog.csdn.net/qq_45626348/article/details/122497059