Leetcode2130. Maximum Twin Sum of a Linked List

In a linked list of size n, where n is even, the ith node (0-indexed) of the linked list is known as the twin of the (n-1-i)th node, if 0 <= i <= (n / 2) - 1.

• For example, if n = 4, then node 0 is the twin of node 3, and node 1 is the twin of node 2. These are the only nodes with twins for n = 4.

The twin sum is defined as the sum of a node and its twin.

Given the head of a linked list with even length, return the maximum twin sum of the linked list.

Example 1:

Input: head = [5,4,2,1]
Output: 6
Explanation:
Nodes 0 and 1 are the twins of nodes 3 and 2, respectively. All have twin sum = 6.
There are no other nodes with twins in the linked list.
Thus, the maximum twin sum of the linked list is 6. 

Example 2:

Input: head = [4,2,2,3]
Output: 7
Explanation:
The nodes with twins present in this linked list are:
- Node 0 is the twin of node 3 having a twin sum of 4 + 3 = 7.
- Node 1 is the twin of node 2 having a twin sum of 2 + 2 = 4.
Thus, the maximum twin sum of the linked list is max(7, 4) = 7. 

Example 3:

Input: head = [1,100000]
Output: 100001
Explanation:
There is only one node with a twin in the linked list having twin sum of 1 + 100000 = 100001.

Constraints:

• The number of nodes in the list is an even integer in the range [2, 105].
• 1 <= Node.val <= 105

import java.util.*;

public class MaximumTwinSum {
    public static void main(String[] args){
        Scanner scan=new Scanner(System.in);
        int n=scan.nextInt();
        LList list=new LList();
        for(int i=0;i<n;i++){
            list.insertFromHead(new ListNode(scan.nextInt()));
        }
        GetSum gs=new GetSum();
        System.out.println(gs.pairSum(list.head.next));
        scan.close();
    }
}
class GetSum{
    public int pairSum(ListNode head) {
        int n=0;
        Stack<Integer> tempo=new Stack<>();
        while(head!=null){
            tempo.push(head.val);
            head=head.next;
            n++;
        }
        n/=2;
        int[] sum=new int[n];
        int max=0;
        int i=0;
        for(;i<n;i++){
            sum[i]=tempo.pop();
        }
        for(int j=0;j<n;j++){
            sum[--i]+=tempo.pop();
            if(sum[i]>max)  max=sum[i];
        }
        return max;
    }
}
class ListNode {
      int val;
      ListNode next;
      ListNode() {}
      ListNode(int val) { this.val = val; }
      ListNode(int val, ListNode next) { this.val = val; this.next = next; }
}
class LList{
    ListNode head;
    int length;
    LList(){
        init();
    }
    private void init(){
        head=new ListNode(-1,null);
        length=0;
    }
    void insertFromHead(ListNode node){
        node.next=head.next;
        head.next=node;
        length++;
    }
}

标签：node,head,int,list,Sum,List,Maximum,twin,sum
来源： https://blog.csdn.net/weixin_47402520/article/details/122494588