《剑指offer》第六_二题(重要!查找二叉树的中序遍历的下一个结点)
作者:互联网
文件一:main.cpp
// 面试题:二叉树的下一个结点 // 题目:给定一棵二叉树和其中的一个结点,如何找出中序遍历顺序的下一个结点? // 树中的结点除了有两个分别指向左右子结点的指针以外,还有一个指向父结点的指针。 #include <iostream> #include "BinaryTree.h" using namespace std; BinaryTreeNode* GetNext(BinaryTreeNode* pNode) { if (pNode == NULL) return NULL; BinaryTreeNode* pNext = NULL;//跟占位符一样的pNext if (pNode->m_pRight != NULL)//第一种情况:我有右孩子 { pNext = pNode->m_pRight;//从这个右孩子开始,一直向下找到没有左孩子为止,则这个节点就是pNext while (pNext->m_pLeft != NULL) pNext = pNext->m_pLeft; } else if (pNode->m_pParent != NULL)//第二种情况:我没有右孩子,而我有父节点 { BinaryTreeNode* pCurrent = pNode; pNext = pNode->m_pParent; while (pNext != NULL && pCurrent == pNext->m_pRight)//从我这个开始向上找父节点,一直找到我这一脉是该父节点的左孩子,如果遇到根节点还没有那就没了 { pCurrent = pNext; pNext = pNext->m_pParent; } } return pNext; } // ====================测试代码==================== void Test(const char* testName, BinaryTreeNode* pNode, BinaryTreeNode* expected) { if (testName != NULL) printf("%s begins: ", testName); BinaryTreeNode* pNext = GetNext(pNode); if (pNext == expected) printf("Passed.\n"); else printf("FAILED.\n"); } // 8 // 6 10 // 5 7 9 11 void Test1_7() { BinaryTreeNode* pNode8 = CreateBinaryTreeNode(8); BinaryTreeNode* pNode6 = CreateBinaryTreeNode(6); BinaryTreeNode* pNode10 = CreateBinaryTreeNode(10); BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5); BinaryTreeNode* pNode7 = CreateBinaryTreeNode(7); BinaryTreeNode* pNode9 = CreateBinaryTreeNode(9); BinaryTreeNode* pNode11 = CreateBinaryTreeNode(11); ConnectTreeNodes(pNode8, pNode6, pNode10); ConnectTreeNodes(pNode6, pNode5, pNode7); ConnectTreeNodes(pNode10, pNode9, pNode11); Test("Test1", pNode8, pNode9); Test("Test2", pNode6, pNode7); Test("Test3", pNode10, pNode11); Test("Test4", pNode5, pNode6); Test("Test5", pNode7, pNode8); Test("Test6", pNode9, pNode10); Test("Test7", pNode11, NULL); DestroyTree(pNode8); } // 5 // 4 // 3 // 2 void Test8_11() { BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5); BinaryTreeNode* pNode4 = CreateBinaryTreeNode(4); BinaryTreeNode* pNode3 = CreateBinaryTreeNode(3); BinaryTreeNode* pNode2 = CreateBinaryTreeNode(2); ConnectTreeNodes(pNode5, pNode4, NULL); ConnectTreeNodes(pNode4, pNode3, NULL); ConnectTreeNodes(pNode3, pNode2, NULL); Test("Test8", pNode5, NULL); Test("Test9", pNode4, pNode5); Test("Test10", pNode3, pNode4); Test("Test11", pNode2, pNode3); DestroyTree(pNode5); } // 2 // 3 // 4 // 5 void Test12_15() { BinaryTreeNode* pNode2 = CreateBinaryTreeNode(2); BinaryTreeNode* pNode3 = CreateBinaryTreeNode(3); BinaryTreeNode* pNode4 = CreateBinaryTreeNode(4); BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5); ConnectTreeNodes(pNode2, NULL, pNode3); ConnectTreeNodes(pNode3, NULL, pNode4); ConnectTreeNodes(pNode4, NULL, pNode5); Test("Test12", pNode5, NULL); Test("Test13", pNode4, pNode5); Test("Test14", pNode3, pNode4); Test("Test15", pNode2, pNode3); DestroyTree(pNode2); } void Test16_17() { BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5); Test("Test16", pNode5, NULL); Test("Test17", NULL, NULL); DestroyTree(pNode5); } int main(int argc, char* argv[]) { Test1_7(); Test8_11(); Test12_15(); Test16_17(); system("pause"); }
文件二:BinaryTree.h
#ifndef BINARY_TREE_H #define BINARY_TREE_H struct BinaryTreeNode { int m_nValue; BinaryTreeNode* m_pLeft; BinaryTreeNode* m_pRight; BinaryTreeNode* m_pParent; }; BinaryTreeNode* CreateBinaryTreeNode(int value); void ConnectTreeNodes(BinaryTreeNode* pParent, BinaryTreeNode* pLeft, BinaryTreeNode* pRight); void PrintTreeNode(BinaryTreeNode* pNode); void PrintTree(BinaryTreeNode* pRoot); void DestroyTree(BinaryTreeNode* pRoot); #endif
文件三:BinaryTree.cpp
#include <iostream> #include "BinaryTree.h" using namespace std; BinaryTreeNode* CreateBinaryTreeNode(int value)//还是建立新节点 { BinaryTreeNode* pNode = new BinaryTreeNode(); pNode->m_nValue = value; pNode->m_pLeft = NULL; pNode->m_pRight = NULL; pNode->m_pParent = NULL; return pNode; } void ConnectTreeNodes(BinaryTreeNode* pParent, BinaryTreeNode* pLeft, BinaryTreeNode* pRight)//一个父节点连接左右两孩子 { if (pParent != NULL) { pParent->m_pLeft = pLeft; pParent->m_pRight = pRight; if (pLeft != NULL) pLeft->m_pParent = pParent; if (pRight != NULL) pRight->m_pParent = pParent; } } void PrintTreeNode(BinaryTreeNode* pNode)//打印当前节点 { if (pNode != NULL) { cout << "value of this node is:" << pNode->m_nValue << endl; if (pNode->m_pLeft != NULL) cout << "value of its left child is:" << pNode->m_pLeft->m_nValue << endl; else cout << "left child is null.\n"; if (pNode->m_pRight != NULL) cout << "value of its right child is: " << pNode->m_pRight->m_nValue << endl; else cout << "right child is null.\n"; } else { cout << "this node is null.\n"; } cout << endl; } void PrintTree(BinaryTreeNode* pRoot)//打印整个树 { PrintTreeNode(pRoot); if (pRoot != NULL) { if (pRoot->m_pLeft != NULL) PrintTree(pRoot->m_pLeft); if (pRoot->m_pRight != NULL) PrintTree(pRoot->m_pRight); } } void DestroyTree(BinaryTreeNode* pRoot)//删除整个树 { if (pRoot != NULL) { BinaryTreeNode* pLeft = pRoot->m_pLeft; BinaryTreeNode* pRight = pRoot->m_pRight; delete pRoot; pRoot = NULL; DestroyTree(pLeft); DestroyTree(pRight); } }
标签:pNode,中序,offer,CreateBinaryTreeNode,pRight,BinaryTreeNode,二叉树,Test,NULL 来源: https://www.cnblogs.com/CJT-blog/p/10467377.html