UVa 10340 - All in All 水题 难度: 0

题目

https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1281

题意

问字符串a能否是字符串b的子序列

思路

明显，计数对的上就行

感想

因为忘了break错了一次 

代码

#include <algorithm>
#include <cassert>
#include <cmath>
#include <cstdio>
#include <cstring>
#include <iostream>
#include <map>
#include <queue>
#include <set>
#include <string>
#include <tuple>
#define LOCAL_DEBUG
using namespace std;
typedef pair<int, int> MyPair;

int main() {
#ifdef LOCAL_DEBUG
    freopen("C:\\Users\\Iris\\source\\repos\\ACM\\ACM\\input.txt", "r", stdin);
    //freopen("C:\\Users\\Iris\\source\\repos\\ACM\\ACM\\output.txt", "w", stdout);
#endif // LOCAL_DEBUG
    int T;
    string a, b;
    for (int ti = 1;cin>>a>>b; ti++) {
        int sza = 0, szb = 0;
        for (sza = 0, szb = 0; sza < a.size() && szb < b.size(); sza++, szb++) {
            while (szb < b.size() && a[sza] != b[szb]) { szb++; }
            if (szb >= b.size())break;
        }
        if (sza == a.size())puts("Yes");
        else puts("No");
    }

    return 0;
}

标签：include,水题,szb,sza,ACM,int,UVa,10340,size
来源： https://www.cnblogs.com/xuesu/p/10463059.html