LeetCode知识点总结 - 231

LeetCode 231. Power of Two

题目

Given an integer n, return true if it is a power of two. Otherwise, return false.

An integer n is a power of two, if there exists an integer x such that n == 2^x.

思路

一个偶数和比它小1的奇数的二进制加起来等于0。

答案

public boolean isPowerOfTwo(int n) {
        return n > 0 && (n & n - 1) == 0;
}

参考：@linfq的答案

标签：知识点,return,power,two,231,integer,LeetCode
来源： https://blog.csdn.net/m0_59773145/article/details/122339393