BUUCTF RE [HDCTF2019]Maze

1.查壳 UPX
2.脱壳 UPX -d

int __cdecl main(int argc, const char **argv, const char **envp)
{
  int v3; // ecx
  int v5; // [esp-4h] [ebp-28h]
  int i; // [esp+10h] [ebp-14h]
  char v7[16]; // [esp+14h] [ebp-10h] BYREF

  sub_401140(aGoThroughTheMa);
  v5 = scanf("%14s", v7);
  if ( (v3 ^ v5) == v3 )
    JUMPOUT(0x40102E);
  for ( i = 0; i <= 13; ++i )
  {
    switch ( v7[i] )
    {
      case 'a':
        --*(_DWORD *)asc_408078;
        break;
      case 'd':
        ++*(_DWORD *)asc_408078;
        break;
      case 's':
        --dword_40807C;
        break;
      case 'w':
        ++dword_40807C;
        break;
      default:
        continue;
    }
  }
  if ( *(_DWORD *)asc_408078 == 5 && dword_40807C == -4 )
  {
    sub_401140(aCongratulation);
    sub_401140(aHereIsTheFlagF);
  }
  else
  {
    sub_401140(aTryAgain);
  }
  return 0;
}

结合

可以看出是一个迷宫
7行排列
db +** ****** **** ******* F**** ****'
db ''

标签：BUUCTF,esp,int,HDCTF2019,char,RE,v3,ebp,v5
来源： https://www.cnblogs.com/socialbiao/p/15693408.html