其他分享
首页 > 其他分享> > BUUCTF RE CrackRTF

BUUCTF RE CrackRTF

作者:互联网

BUUCTF RE CrackRTF

int __cdecl main_0(int argc, const char **argv, const char **envp)
{
  DWORD v3; // eax
  DWORD v4; // eax
  char Str[260]; // [esp+4Ch] [ebp-310h] BYREF
  int v7; // [esp+150h] [ebp-20Ch]
  char String1[260]; // [esp+154h] [ebp-208h] BYREF
  char Destination[260]; // [esp+258h] [ebp-104h] BYREF

  memset(Destination, 0, sizeof(Destination));
  memset(String1, 0, sizeof(String1));
  v7 = 0;
  printf("pls input the first passwd(1): ");
  scanf("%s", Destination);
  if ( strlen(Destination) != 6 )    ///输入长度为6
  {
    printf("Must be 6 characters!\n");
    ExitProcess(0);
  }
  v7 = atoi(Destination);
  if ( v7 < 100000 )
    ExitProcess(0);
  strcat(Destination, "@DBApp"); ///进行链接  
  v3 = strlen(Destination);     ///v3=12   
  sub_40100A((BYTE *)Destination, v3, String1);
  if ( !_strcmpi(String1, "6E32D0943418C2C33385BC35A1470250DD8923A9") )
  {
    printf("continue...\n\n");
    printf("pls input the first passwd(2): ");
    memset(Str, 0, sizeof(Str));
    scanf("%s", Str);
    if ( strlen(Str) != 6 )
    {
      printf("Must be 6 characters!\n");
      ExitProcess(0);
    }
    strcat(Str, Destination);
    memset(String1, 0, sizeof(String1));
    v4 = strlen(Str);
    sub_401019((BYTE *)Str, v4, String1);
    if ( !_strcmpi("27019e688a4e62a649fd99cadaafdb4e", String1) )
    {
      if ( !(unsigned __int8)sub_40100F(Str) )
      {
        printf("Error!!\n");
        ExitProcess(0);
      }
      printf("bye ~~\n");
    }
  }
  return 0;
}

标签:BUUCTF,CrackRTF,Destination,char,RE,ebp,Str,printf,String1
来源: https://www.cnblogs.com/socialbiao/p/15664587.html