1081 检查密码 (15 分)

题目链接

算法分析

用两个变量ap_digit和ap_zm来记录是否有数字和字母出现,然后进行特判并输出就好了.

测试点

测试点2是在考察是否有考虑字符串中含有空格

代码实现

#include<bits/stdc++.h>
using namespace std;

int main(){
	string s;
	int n;
	scanf("%d", &n);
	getline(cin, s);
	for(int i = 1; i <= n; ++ i){
		getline(cin, s);
		int len = s.size();
		if(len < 6){
			puts("Your password is tai duan le.");
			continue;
		}
		int ap_digit = 0, ap_zm = 0;
		for(int j = 0; j < len; ++ j){
			if(isdigit(s[j])) ap_digit = 1;
			else if(islower(s[j]) || isupper(s[j])) ap_zm = 1;
			else if(s[j] == '.') continue;
			else{
				ap_digit = ap_zm = 0;
				break;
			}
		}
		if(ap_digit && ap_zm) puts("Your password is wan mei.");
		else if(ap_digit && !ap_zm) puts("Your password needs zi mu.");
		else if(!ap_digit && ap_zm) puts("Your password needs shu zi.");
		else puts("Your password is tai luan le.");
	}
	return 0;
}

标签：zm,digit,15,puts,测试点,int,代码,else,ap
来源： https://blog.csdn.net/qq_34771124/article/details/121686194