530、二叉搜索树的最小绝对差

基本思想：

中序遍历

具体实现：

代码：

class Solution {
    TreeNode pre;//记录上一个遍历的节点
    int result = Integer.MAX_VALUE;
    public int getMinimumDifference(TreeNode root) {
        if (root == null) return 0 ;
        traversal(root);
        return result;
    }

    public void traversal(TreeNode root){
        if (root == null) return;
        traversal(root.left);
        if (pre != null) result = Math.min(result, root.val - pre.val);
        pre = root;
        traversal(root.right);
    }
}

迭代法：

class Solution {
    TreeNode pre;
    Stack<TreeNode> stack;
    public int getMinimumDifference(TreeNode root) {
        if (root == null) return 0;
        stack = new Stack<>();
        TreeNode cur = root;
        int result = Integer.MAX_VALUE;
        while (cur != null || !stack.isEmpty()) {
            if (cur != null) {
                stack.push(cur); // 将访问的节点放进栈
                cur = cur.left; // 左
            }else {
                cur = stack.pop(); 
                if (pre != null) { // 中
                    result = Math.min(result, cur.val - pre.val);
                }
                pre = cur;
                cur = cur.right; // 右
            }
        }
        return result;
    }
}

标签：pre,TreeNode,cur,二叉,力扣,result,530,null,root
来源： https://www.cnblogs.com/zhaojiayu/p/15564262.html