Django中实现简单的CRUD

# models.py
class User(models.Model):
    id = models.IntegerField(primary_key=True)
    username = models.CharField(max_length=32, unique=True)

# views.py
@require_GET
def get_user_list(request):
    users = User.objects.all()
    data = [{'id': user.id, 'username': user.username} for user in users]
    return JsonResponse({'code': 200, 'data': data, 'message': '查询成功'})


@require_GET
def add_user(request):
    request.encoding = 'utf-8'
    if request.GET:
        username = request.GET['username']
        id = request.GET['id']
        if username and id:
            User.objects.create(id=id, username=username)
            return JsonResponse({'code': 200, 'msg': '添加成功'})
        else:
            return HttpResponse('请传入username和id')
    else:
        return HttpResponse('请求方式错误')


@require_GET
def delete_user(request):
    request.encoding = 'utf-8'
    if request.GET:
        id = request.GET['id']
        if username:
            User.objects.filter(id=id).delete()
            return JsonResponse({'code': 200, 'msg': '删除成功'})
        else:
            return HttpResponse('请传入id')
    else:
        return HttpResponse('请求方式错误')


@require_GET
def update_use(request):
    request.encoding = 'utf-8'
    if request.GET:
        id = request.GET['id']
        username = request.GET['username']
        if username and id:
            User.objects.filter(id=id).update(username=username)
            return JsonResponse({'code': 200, 'msg': '修改成功'})
        else:
            return HttpResponse('请传入username和id')
    else:
        return HttpResponse('请求方式错误')

标签：username,return,GET,CRUD,request,Django,简单,HttpResponse,id
来源： https://www.cnblogs.com/huturen/p/15504767.html