412. Fizz Buzz

知识点： 列表 list append % 求模运算（余数）

class Solution:
    def fizzBuzz(self, n: int) -> List[str]:
        res = []
        for i in range(1, n+1):
            # if not i%15:
            #     tmp = "FizzBuzz"
            # elif not i%3:
            #     tmp = "Fizz"
            # elif not i%5:
            #     tmp = "Buzz"
            # else:
            #     tmp = str(i)

            tmp = ""
            if not i%3:
                tmp += "Fizz"
            if not i%5:
                tmp += "Buzz"
            if not tmp:
                tmp = str(i)
            
            res.append(tmp)
        
        return res
        
        # return ["Fizz"[i%3*4:] + "Buzz"[i%5*4:] or str(i) for i in range(1,n+1)]

414. 第三大的数

知识点： 条件语句 if elif else 条件表达式 one if … else two

class Solution:
    def thirdMax(self, nums: List[int]) -> int:
        x = y = z = -inf
        for n in nums:
        	# 方法一
            # if n > x:
            #     x, n = n, x # 替换出 x
            # if x > n > y:
            #     y, n = n, y
            # if y > n > z:
            #     z = n
			
			# 方法二
            if n > x:
                z, y, x = y, x, n  # 依次替换
            elif x > n > y:
                z, y = y, n              
            elif y > n > z:
                z = n                

        return x if z == -inf else z

列表(list) 集合(set) 字典(dict) 排序(sorted,sort)

class Solution:
    def thirdMax(self, nums: List[int]) -> int:
        d = {}
        for n in nums:
            d[n] = d.get(n, 0) + 1
        return max(d) if len(d) < 3 else sorted(d)[-3]
                
        # return x[-3] if len(x:=sorted(list(set(nums)))) > 2 else max(x)

标签：tmp,elif,return,int,else,401,420,i%,Leetcode
来源： https://blog.csdn.net/weixin_43955170/article/details/121077848