对于时间冲突的判断问题

List<Fa1> ydqs=faMapper.selectQs(fa1);
Date start=fa1.getKs();
Date end =fa1.getJs();
if(start.after(new Date())&&start.before(end)){
    if(ydqs.size()==0){
        fa1.setIdd(UUIDUtil.getUUID());
        fa1.setGl(UUIDUtil.getUUID());
         faMapper.insertFa1(fa1);

}else if(start.after(ydqs.get(ydqs.size()-1).getJs())){
        fa1.setIdd(UUIDUtil.getUUID());
        fa1.setGl(UUIDUtil.getUUID());
        faMapper.insertFa1(fa1);
    }else if(end.before(ydqs.get(0).getKs())){
        fa1.setIdd(UUIDUtil.getUUID());
        fa1.setGl(UUIDUtil.getUUID());
        faMapper.insertFa1(fa1);
    }else{
        for(int i=0;i<ydqs.size();i++){
            if(start.after(ydqs.get(i).getJs())&&end.before(ydqs.get(i+1).getKs())){
                fa1.setIdd(UUIDUtil.getUUID());
                fa1.setGl(UUIDUtil.getUUID());
                faMapper.insertFa1(fa1);
            }
        }
    }
}else {
    fa1.setIdd(null);
    faMapper.insertFa1(fa1);
}

标签：判断,faMapper,UUIDUtil,对于,fa1,start,ydqs,冲突,getUUID
来源： https://blog.csdn.net/weixin_46071489/article/details/121074713