消息中间件RabbitMQ(二)

上篇文章主要说大概逻辑，这篇就文章用代码验证细节。

1、当交换机为Direct类型，当多个相同路由key和队列连接时，发送消息时，队列是否都会收到消息？ 答案是肯定的。

发送端：

using (IConnection con = conFactory.CreateConnection())//创建连接对象
{
    using (IModel channel = con.CreateModel())//创建连接会话对象
    {
        channel.QueueDeclare(queue1, false, false, false, null);
        channel.QueueDeclare(queue2, false, false, false, null);
        channel.QueueDeclare(queue3, false, false, false, null);

        channel.ExchangeDeclare(exchange1, ExchangeType.Direct);
        
        channel.QueueBind(queue1, exchange1, routingKey1);
        channel.QueueBind(queue2, exchange1, routingKey2);
        channel.QueueBind(queue3, exchange1, routingKey2);

        while (true)
        {
            Console.WriteLine("消息内容:");
            var message = Console.ReadLine();
            byte[] body = Encoding.UTF8.GetBytes(message);
            channel.BasicPublish(exchange1, routingKey2, null, body);
            channel.BasicPublish(exchange1, routingKey1, null, body);
            Console.WriteLine("成功发送消息:" + message);
        }
    }
}

消费端：

using (IConnection conn = connFactory.CreateConnection())
{
    using (IModel channel = conn.CreateModel())
    {
        var consumer = new EventingBasicConsumer(channel);
        channel.BasicConsume(queue1, false, consumer);
        channel.BasicConsume(queue2, false, consumer);
        channel.BasicConsume(queue3, false, consumer);
        consumer.Received += (model, ea) =>
        {
            byte[] message = ea.Body.ToArray();
            Console.WriteLine($"交换机：{ea.Exchange} 路由Key：{ea.RoutingKey} 接收到信息为:{Encoding.UTF8.GetString(message)}");
            channel.BasicAck(ea.DeliveryTag, false);
        };
        Console.ReadKey();
    }
}

结果：

 

2、当交换器的类型是Fanout类型，与之连接多个队列，发送消息时，是否所有与之连接的队列都会收到？ 答案是肯定的。

 

发送端：

using (IConnection con = conFactory.CreateConnection())//创建连接对象
{
    using (IModel channel = con.CreateModel())//创建连接会话对象
    {
        channel.QueueDeclare(queue1, false, false, false, null);
        channel.QueueDeclare(queue2, false, false, false, null);
        channel.QueueDeclare(queue3, false, false, false, null);

        channel.ExchangeDeclare(exchange2, ExchangeType.Fanout);
        channel.QueueBind(queue1, exchange2, routingKey2);
        channel.QueueBind(queue2, exchange2, routingKey2);
        channel.QueueBind(queue3, exchange2, routingKey2);

        while (true)
        {
            Console.Write("消息内容:");
            var message = Console.ReadLine();
            byte[] body = Encoding.UTF8.GetBytes(message);
            channel.BasicPublish(exchange2, routingKey2, null, body);
            Console.WriteLine("成功发送消息:" + message);
        }
    }

消费端 代码不变。

结果：

 3、当一个队列有多个消费者，是否所有的消费者都能接收到消息？ 答案是否定的。会轮询发送给监听的所有消费者

发送端：代码不变

消费端：添加一个消费者

using (IConnection conn = connFactory.CreateConnection())
{
    using (IModel channel = conn.CreateModel())
    {
        var consumer = new EventingBasicConsumer(channel);

        var consumer2=new EventingBasicConsumer(channel);
        channel.BasicConsume(queue1, false, consumer);
        channel.BasicConsume(queue2, false, consumer);
        channel.BasicConsume(queue3, false, consumer);

        channel.BasicConsume(queue1, false, consumer2);
        channel.BasicConsume(queue2, false, consumer2);
        channel.BasicConsume(queue3, false, consumer2);

        consumer.Received += (model, ea) =>
        {
            byte[] message = ea.Body.ToArray();
            Console.WriteLine($"消费者:consumer1  交换机：{ea.Exchange} 路由Key：{ea.RoutingKey} 接收到信息为:{Encoding.UTF8.GetString(message)}");
            channel.BasicAck(ea.DeliveryTag, false);
        };

        consumer2.Received += (model, ea) =>
        {
            byte[] message = ea.Body.ToArray();
            Console.WriteLine($"消费者:consumer2 交换机：{ea.Exchange} 路由Key：{ea.RoutingKey} 接收到信息为:{Encoding.UTF8.GetString(message)}");
            channel.BasicAck(ea.DeliveryTag, false);
        };

        Console.ReadKey();
    }
}

结果：

标签：false,ea,RabbitMQ,消息中间件,Console,message,consumer,channel
来源： https://www.cnblogs.com/MicroHeart/p/14688585.html