根据时间（秒数）获得两段时间的间隔

得到两段时间差转为int类型，并作为参数传入下面的方法之中

                    TimeSpan ts = DataConvert.getTime(Model.outTime).Subtract(DataConvert.getTime(Model.inTime));
                    int sec = (int)ts.TotalSeconds;
                    string parkMins= parseTimeSeconds(sec);

下面的方法需要传入的参数为秒数也可以通过两段时间相减取得

  ///<summary>
        ///由秒数得到日期几天几小时。。。
        ///</summary
        ///<param name="t">秒数</param>
        ///<param name="type">0：转换后带秒，1:转换后不带秒</param>
        ///<returns>几天几小时几分几秒</returns>
        public static string parseTimeSeconds(int t, int type = 1)
        {
            string r = "";
            int day, hour, minute, second;
            if (t >= 86400) //天,
            {
                day = Convert.ToInt16(t / 86400);
                hour = Convert.ToInt16((t % 86400) / 3600);
                minute = Convert.ToInt16((t % 86400 % 3600) / 60);
                second = Convert.ToInt16(t % 86400 % 3600 % 60);
                if (type == 0)
                    r = day + ("天") + hour + ("小时") + minute + ("分") + second + ("秒");
                else
                    r = day + ("天") + hour + ("小时") + minute + ("分");

            }
            else if (t >= 3600)//时,
            {
                hour = Convert.ToInt16(t / 3600);
                minute = Convert.ToInt16((t % 3600) / 60);
                second = Convert.ToInt16(t % 3600 % 60);
                if (type == 0)
                    r = hour + ("小时") + minute + ("分") + second + ("秒");
                else
                    r = hour + ("小时") + minute + ("分");
            }
            else if (t >= 60)//分
            {
                minute = Convert.ToInt16(t / 60);
                second = Convert.ToInt16(t % 60);
                r = minute + ("分") + second + ("秒");
            }
            else
            {
                second = Convert.ToInt16(t);
                r = second + ("秒");
            }
            return r;
        }

标签：ToInt16,Convert,3600,秒数,60,second,时间,两段,minute
来源： https://www.cnblogs.com/zzmpro/p/15424340.html