PTA 乙级 1077 互评成绩计算 (20 分)
作者:互联网
做的十分暴力
不多说了
直接上代码吧
python也试着写了写,总共不超过10行
自行摸索吧(嘿嘿)
C++
1 #include <iostream> 2 #include <vector> 3 #include <algorithm> 4 #include <cmath> 5 using namespace std; 6 7 int main() { 8 int N = 0, M = 0; 9 cin >> N >> M; 10 for (int i = 0; i < N; ++i) { 11 int G1 = 0; 12 cin >> G1; 13 vector<int> G2; 14 for (int j = 0; j < N - 1; ++j) { 15 int score = 0; 16 cin >> score; 17 if(score <= M && score >= 0) G2.push_back(score); 18 } 19 sort(G2.begin(), G2.end()); 20 G2.pop_back(); 21 G2.erase(G2.begin()); 22 int sum = 0; 23 for(int j : G2) { 24 sum += j; 25 } 26 float G2_avg = sum / G2.size(); 27 cout << round((G2_avg + G1) / 2) << endl; 28 } 29 return 0; 30 }
标签:20,G2,int,1077,sum,cin,互评,score,include 来源: https://www.cnblogs.com/SCP-514/p/15363154.html