noi1.2.25
作者:互联网
#include <stdio.h>
#include <stdlib.h>
int main()
{
int x = 199;
int y = 677 +6*7 +6;
for(int i = x;i<=y;i++){
if(i%7i/81&&i/7%7i/9%9&&i/49==i%9){
x=i;
printf("%d\n",x);
}
}
printf("%d%d%d\n",x/49,x/7%7,x%7);
printf("%d%d%d\n",x/81,x/9%9,x%9);
return 0;
}
标签:noi1.2,7%,25,int,d%,9%,7i,printf 来源: https://blog.csdn.net/gggggym/article/details/120581056