1019 General Palindromic Number (20 分) 【难度: 简单 / 知识点: 判断回文】

https://pintia.cn/problem-sets/994805342720868352/problems/994805487143337984

#include<bits/stdc++.h>
using namespace std;
int n,b;
void f(int n,int b)
{
    if(!n)
    {
        cout<<"Yes"<<endl<<0;
        return;
    } 
    vector<int>s,temp;
    while(n) s.push_back(n%b),n/=b;
    temp=s;
    reverse(s.begin(),s.end());
    if(temp==s) puts("Yes");
    else puts("No");
    for(int i=0;i<s.size();i++)
    {
        if(i) cout<<" ";
        cout<<s[i];
    }
}
int main(void)
{
    cin>>n>>b;
    f(n,b);
    return 0;
}

标签：知识点,20,temp,puts,Palindromic,int,No,cn
来源： https://blog.csdn.net/qq_46527915/article/details/120256864