判断及格与否

public class Demo08 {
    public static void main(String[] args) {
        /*
        三元运算符
        X ? Y : Z
        如果x==true，则结果为Y，否则返回Z.
         */
        int score = 60;
        //判断及格与否
        String perform = score < 60?"不及格":"及格";
        System.out.println(perform);
    }
}

输出：

及格

Process finished with exit code 0

标签：及格,判断,String,perform,与否,60,score,public
来源： https://www.cnblogs.com/gracewqy/p/15164943.html