Codeforces Round #650 (Div. 3)

比赛链接：Here

1367A. Short Substrings

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 Description 

 

一个字符串 abac，然后把所有长度为2的子串加起来变成新串，abbaac，由 ab ba ac组成。现在给出新串，找出原串。

1367B. Even Array

1367C. Social Distance

1367D. Task On The Board

1367E. Necklace Assembly

1367F1. Flying Sort (Easy Version)

标签：新串,Even,ac,ab,abac,Flying,Codeforces,650,Div
来源： https://www.cnblogs.com/RioTian/p/15149661.html