8-1 最大连续和

#include <bits/stdc++.h>
using namespace std;
const int maxn = 10010;
int a[maxn], s[maxn];
int main() {
  int n;
  int mins = 999999, ans = -999999;
  cin >> n;
  for (int i = 1; i <= n; i++) {
    cin >> a[i];
    s[i] = s[i - 1] + a[i];
    mins = min(mins, s[i]);
    ans = max(ans, s[i] - mins);
  }
  cout << ans;
}

Make your program run faster depending on its math feature.

标签：最大,int,999999,maxn,连续,ans,mins,cout
来源： https://www.cnblogs.com/vv123/p/15113712.html