poj 3083(不是特别难,但是很麻烦)
作者:互联网
#include<iostream> #include<cstdio> #include<cstring> using namespace std; int k,t,w,h,sx,sy,sum,ex,ey; int idx[45][45],data[45][45],ans[3]; char c[45][45]; void print(){ for(int i=0;i<h;i++){ for(int j=0;j<w;j++){ cout<<data[i][j]<<"\t"; } cout<<endl; } cout<<endl; } void dfs_shortest(int i,int j){ int r,c; if(i<0||j<0||i>=h||j>=w)return; if(idx[i][j]>k&&data[i][j]!=0){ idx[i][j] = k; } if(data[i][j] == -2)return; // print(); k++; for(r=-1;r<=1;r++) for(c=-1;c<=1;c++) if((r*c==0)&&!(r==0&&c==0)) if(i+r>=0&&i+r<h&&j+c>=0&&j+c<w) if(idx[i+r][j+c]>k&&data[i+r][j+c]!=0){ idx[i+r][j+c] = k; dfs_shortest(i+r,j+c); } k--; } bool dfs_left(int direction,int i,int j){//direction=1向东direction=2向南direction=3向西direction=4向北 int r,c; // cout<<i<<" "<<j<<" "<<k<<endl; // system("pause"); if(i<0||j<0||i>=h||j>=w)return false; if(data[i][j]==0)return false; if(data[i][j]==-2)return true; k++; if(direction==1){ if(dfs_left(4,i-1,j)) return true; if(dfs_left(1,i,j+1)) return true; if(dfs_left(2,i+1,j)) return true; if(dfs_left(3,i,j-1)) return true; } if(direction==2){ if(dfs_left(1,i,j+1)) return true; if(dfs_left(2,i+1,j)) return true; if(dfs_left(3,i,j-1)) return true; if(dfs_left(4,i-1,j)) return true; } if(direction==3){ if(dfs_left(2,i+1,j)) return true; if(dfs_left(3,i,j-1)) return true; if(dfs_left(4,i-1,j)) return true; if(dfs_left(1,i,j+1)) return true; } if(direction==4){ if(dfs_left(3,i,j-1)) return true; if(dfs_left(4,i-1,j)) return true; if(dfs_left(1,i,j+1)) return true; if(dfs_left(2,i+1,j)) return true; } return false; } bool dfs_right(int direction,int i,int j){ if(i<0||j<0||i>=h||j>=w)return false; if(data[i][j]==0)return false; if(data[i][j]==-2)return true; k++; if(direction==1){ if(dfs_right(2,i+1,j)) return true; if(dfs_right(1,i,j+1)) return true; if(dfs_right(4,i-1,j)) return true; if(dfs_right(3,i,j-1)) return true; } if(direction==2){ if(dfs_right(3,i,j-1)) return true; if(dfs_right(2,i+1,j)) return true; if(dfs_right(1,i,j+1)) return true; if(dfs_right(4,i-1,j)) return true; } if(direction==3){ if(dfs_right(4,i-1,j)) return true; if(dfs_right(3,i,j-1)) return true; if(dfs_right(2,i+1,j)) return true; if(dfs_right(1,i,j+1)) return true; } if(direction==4){ if(dfs_right(1,i,j+1)) return true; if(dfs_right(4,i-1,j)) return true; if(dfs_right(3,i,j-1)) return true; if(dfs_right(2,i+1,j)) return true; } return false; } int main(){ int i,j; scanf("%d",&t); while(t--){ scanf("%d%d",&w,&h); memset(data,0,sizeof(data)); for(i=0;i<h;i++){ scanf("%s",c[i]); for(j=0;j<w;j++) if(c[i][j]=='.'){ data[i][j] = 1; } else if(c[i][j]=='S'){ data[i][j] = -1; sx = i; sy = j; } else if(c[i][j]=='E'){ data[i][j] = -2; ex = i; ey = j; } } sum = 1000000; memset(idx,0x7f,sizeof(idx)); k = 1; dfs_shortest(sx,sy); ans[2] = idx[ex][ey]; k = 1; if(sx==0) dfs_left(1,0,sy); else if(sy==0) dfs_left(4,sx,0); else if(sx==h-1) dfs_left(3,h-1,sy); else if(sy==w-1) dfs_left(2,sx,w-1); ans[0] = k; k = 1; if(sx==0) dfs_right(3,0,sy); else if(sy==0) dfs_right(2,sx,0); else if(sx==h-1) dfs_right(1,h-1,sy); else if(sy==w-1) dfs_right(4,sx,w-1); ans[1] = k; printf("%d %d %d\n",ans[0],ans[1],ans[2]); // dfs_left_first_start(sx,sy); // ans[0] = k+2; // k = 0; // dfs_right_first_start(sx,sy); // ans[1] = k+2; } return 0; }
标签:direction,right,return,dfs,poj,麻烦,true,3083,left 来源: https://www.cnblogs.com/stevenzrx/p/15102741.html