单片机：分别控制两个LED灯不同时长亮

#include <reg51.h>
#define uchar unsigned char
#define uint unsigned int
sbit led1=P1^0;
sbit led2=P1^3;
sbit k1=P3^2;
sbit k2=P3^3;
uchar num0,num1;
void init()
{
    TMOD=0x11; //设置定时器0位工作模式1(M1,M0位0，1)
TH0=(65536-45872)/256; //装初值11.0592M晶振定时50ms数为45872
TL0=(65536-45872)%256;
    TH0=0X2C;
TL0=0X00;
TH1=0X3C;
TL1=0X00;
EA=1; //开总中断
ET0=1; //开定时器0中断

ET1=1;
TR1=1;
    TR0=1; //启动定时器0
}  

void main()
{ 
init();
while(1)
{
if(num0==20) 
{
led1=~led1; //让发光管状态取反
num0=0;
}
else
{if(num1==20) 
{
led2=~led2; //让发光管状态取反
num1=0;
}
}
}
}
void T0_time()interrupt 1
{
TR0=0;
TH0=(65536-46873)/256; //重新装载初值
TH0=0X2C;
TL0=0X00;
TR0=1;
//TL0=(65536-46873)%256;
num0++; 
}
void T1_time()interrupt 3
{
TR1=0;
TH1=(65536-45872)/256; //重新装载初值
TL1=(65536-45872)%256;
TH1=0X3C;
TL1=0X00;
TR1=1;
num1++; 
}

标签：LED,num1,单片机,0X00,45872,长亮,num0,65536,256
来源： https://www.cnblogs.com/xkdn/p/15088388.html