2021.08.01 P3377 左偏树模板

2021.08.01 P3377 左偏树模板

P3377 【模板】左偏树（可并堆） - 洛谷 | 计算机科学教育新生态 (luogu.com.cn)

#include<iostream>
#include<cstdio>
#include<algorithm>
using namespace std;
#define aa 100010
int n,m,vis[aa],fa[aa];
struct node{
	int ls,rs,val,dis;
}a[aa];
inline int read(){
	int s=0,w=1;
	char ch=getchar();
	while(ch<'0'||ch>'9'){
		if(ch=='-')w=-1;
		ch=getchar();
	}
	while(ch<='9'&&ch>='0'){
		s=s*10+ch-'0';
		ch=getchar();
	}
	return s*w;
}
int find(int x){
	return fa[x]==x?x:fa[x]=find(fa[x]);
}
int merge(int x,int y){
	if(!x||!y)return x+y;
	if(a[x].val ==a[y].val?x>y:a[x].val>a[y].val)
		swap(x,y);//x<y
	a[x].rs =merge(a[x].rs ,y);
	if(a[a[x].ls ].dis <a[a[x].rs].dis)
		swap(a[x].ls,a[x].rs);
	fa[x]=fa[a[x].ls]=fa[a[x].rs]=x;
	a[x].dis=a[a[x].rs].dis+1;
	return x;
}
void pop(int x){
	vis[x]=1;
	fa[a[x].ls]=a[x].ls;
	fa[a[x].rs]=a[x].rs;
	fa[x]=merge(a[x].ls,a[x].rs);
	a[x].ls=a[x].rs=a[x].dis=0;
}
int main(){
	n=read();m=read();
	for(int i=1;i<=n;i++)a[i].val=read(),fa[i]=i;
	a[0].dis=-1;
	while(m--){
		int x;
		x=read();
		if(x==1){
			int u,v,ui,vi;
			u=read();v=read();
			if(vis[u]||vis[v])continue;
			ui=find(u);vi=find(v);
			if(ui!=vi)fa[ui]=fa[vi]=merge(ui,vi);
		}else if(x==2){
			int u,ui;
			u=read();
			if(vis[u]){
				cout<<"-1"<<endl;
				continue;
			}
			ui=find(u);
			cout<<a[ui].val<<endl;
			pop(ui);
		}
	}
	//for(int i=1;i<=n;i++)cout<<fa[i]<<" ";cout<<endl;//
	return 0;
}

标签：aa,ch,val,int,2021.08,fa,P3377,左偏
来源： https://www.cnblogs.com/eleveni/p/15086768.html