poj 2583(水题)
作者:互联网
#include<iostream> #include<cstdio> using namespace std; int main(){ int k1,k2,k3,a[3]; while(scanf("%d%d%d",&k1,&k2,&k3)==3){ a[0] = k1-3*k2+3*k3; a[1] = 3*k1-8*k2+6*k3; a[2] = 6*k1-15*k2+10*k3; printf("%d %d %d\n",a[0],a[1],a[2]); } return 0; }
标签:2583,水题,int,d%,k3,k2,k1,poj,include 来源: https://www.cnblogs.com/stevenzrx/p/15085212.html