UVA-10361 Automatic Poetry

原题连接：

https://vjudge.net/problem/UVA-10361

AC代码：

#include <bits/stdc++.h>
using namespace std;

void getsi(char str[])
{
    char c;
    int i = 0;
    while (c = getchar())
    {
        if (c != '<' && c != '>' && c != '\n')
        {
            str[i++] = c;
        }
        else
        {
            str[i] = '\0';
            return;
        }
    }
}

int main()
{
    int n;
    cin >> n;
    getchar();
    while (n--)
    {
        char s1[101], s2[101], s3[101], s4[101], s5[101], s[101];
        getsi(s1);
        getsi(s2);
        getsi(s3);
        getsi(s4);
        getsi(s5);
        fgets(s, 101, stdin);
        s[strlen(s) - 4] = '\0';
        cout << s1 << s2 << s3 << s4 << s5 << endl;
        cout << s << s4 << s3 << s2 << s5 << endl;
    }
    return 0;
}

参考了网上大佬的思路，精简美观
自己写的就乱七八糟，我果然还是太菜了

标签：int,Automatic,char,getsi,str,UVA,101,10361
来源： https://blog.csdn.net/sjyisdog/article/details/119172296