CTF-Streamgame2-writeup
作者:互联网
Streamgame2
题目信息:
附件:
streamgame2.py
from flag import flag
assert flag.startswith("flag{")
assert flag.endswith("}")
assert len(flag)==27
def lfsr(R,mask):
output = (R << 1) & 0xffffff
i=(R&mask)&0xffffff
lastbit=0
while i!=0:
lastbit^=(i&1)
i=i>>1
output^=lastbit
return (output,lastbit)
R=int(flag[5:-1],2)
mask=0x100002
f=open("key","ab")
for i in range(12):
tmp=0
for j in range(8):
(R,out)=lfsr(R,mask)
tmp=(tmp << 1)^out
f.write(chr(tmp))
f.close()
key
解题思路:
1.观察py文件,可知flag的长度为27格式为flag{xxxx}其中xxxx为19位的二进制串
2.观察py文件,可知key文件是该脚本的输出,脚本中每轮循环输出1个字节,共输出12字节的数据
3.由于xxxx只有21位,考虑直接爆破
附件:
def lfsr(R,mask):
output = (R << 1) & 0xffffff
i=(R&mask)&0xffffff
lastbit=0
while i!=0:
lastbit^=(i&1)
i=i>>1
output^=lastbit
return (output,lastbit)
with open("key","rb") as f:
filek = f.read(12)
res = bytes()
for a in range(2**21):
R=a
mask=0x100002
for i in range(12):
tmp=0
for j in range(8):
(R,out)=lfsr(R,mask)
tmp=(tmp << 1)^out
res += tmp.to_bytes(length=1,byteorder='big',signed=False)
print(a,res,filek)
if res == filek:
break
else:
res = bytes()
FLAG
flag{110111100101001101001}
作者:damedane-qiuqiu
标签:tmp,writeup,mask,flag,CTF,lfsr,output,Streamgame2,range 来源: https://www.cnblogs.com/lingxuer/p/15022256.html