【PAT乙级】1034 有理数四则运算 (20 分)

题目地址

#include<cstdio>
#include<iostream>
#include<string>
using namespace std;
long long int a,b,c,d,sum1,sum2; 
int gcd(int a,int b)
{
	if(b==0) return a;
	else return gcd(b,a%b);
}
void print(long long int a,long long int b)
{
	long long int s;
	double flag; flag=a*1.0/b;
	s=a/b;
	a=a-s*b;
	long long int temp=gcd(a,b);
	a=a/temp;
	b=b/temp;
	if(flag<0)	
	{
		a=abs(a),b=abs(b),s=abs(s);
		if(s||a==0) 
		{
			if(a==0) printf("(%d)",s*-1);
			else  printf("(%d %d/%d)",s*-1,a,b);
		}
		else printf("(%d/%d)",a*-1,b);
	}
	else
	{
		if(s||a==0) 
		{
			if(a==0) printf("%d",s);
			else printf("%d %d/%d",s,a,b);
		}
		else printf("%d/%d",a,b);	
	} 
}
int main(void)
{
	scanf("%lld/%lld %lld/%lld",&a,&b,&c,&d);
	sum2=b*d/gcd(b,d);
	sum1=a*sum2/b+c*sum2/d; 
	print(a,b); printf(" + "); print(c,d); printf(" = "); print(sum1,sum2); printf("\n");
	sum1=a*sum2/b-c*sum2/d; 
	print(a,b); printf(" - "); print(c,d); printf(" = "); print(sum1,sum2); printf("\n");
	sum2=b*d;
	sum1=a*c;
	print(a,b); printf(" * "); print(c,d); printf(" = "); print(sum1,sum2); printf("\n");
	
	sum1=a*d;
	sum2=b*c;
	if(c==0)
	{
		print(a,b); printf(" / "); print(c,d); printf(" = "); printf("Inf"); printf("\n");
	}
	else 
	{	
		print(a,b); printf(" / "); print(c,d); printf(" = "); print(sum1,sum2); printf("\n");
	}
	return 0;
}

标签：PAT,int,sum2,long,sum1,printf,print,20,1034
来源： https://blog.csdn.net/qq_46527915/article/details/118580316