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6 pandas人口分析案例

2021-06-16 13:33:47 作者：互联网

需求：
- 导入文件，查看原始数据
- 将人口数据和各州简称数据进行合并
- 将合并的数据中重复的abbreviation列进行删除
- 查看存在缺失数据的列
- 找到有哪些state/region使得state的值为NaN，进行去重操作
- 为找到的这些state/region的state项补上正确的值，从而去除掉state这一列的所有NaN
- 合并各州面积数据areas
- 我们会发现area(sq.mi)这一列有缺失数据，找出是哪些行
- 去除含有缺失数据的行
- 找出2010年的全民人口数据
- 计算各州的人口密度
- 排序，并找出人口密度最高的州

import numpy as np
import pandas as pd
from pandas import DataFrame

#导入文件，查看原始数据
abb = pd.read_csv('./data/state-abbrevs.csv') #state(州的全称)abbreviation（州的简称）

area = pd.read_csv('./data/state-areas.csv') #state州的全称，area (sq. mi)州的面积

pop = pd.read_csv('./data/state-population.csv')#state/region简称，ages年龄，year时间，population人口数量

#将人口数据和各州简称数据进行合并
abb_pop = pd.merge(abb,pop,left_on='abbreviation',right_on='state/region',how='outer')
abb_pop.head()

	state	abbreviation	state/region	ages	year	population
0	Alabama	AL	AL	under18	2012	1117489.0
1	Alabama	AL	AL	total	2012	4817528.0
2	Alabama	AL	AL	under18	2010	1130966.0
3	Alabama	AL	AL	total	2010	4785570.0
4	Alabama	AL	AL	under18	2011	1125763.0

#将合并的数据中重复的abbreviation列进行删除
abb_pop.drop(labels='abbreviation',axis=1,inplace=True)

abb_pop.head()

	state	state/region	ages	year	population
0	Alabama	AL	under18	2012	1117489.0
1	Alabama	AL	total	2012	4817528.0
2	Alabama	AL	under18	2010	1130966.0
3	Alabama	AL	total	2010	4785570.0
4	Alabama	AL	under18	2011	1125763.0

#查看存在缺失数据的列
#方式1：isnull，notll，any，all
abb_pop.isnull().any(axis=0)
#state,population这两列中是存在空值

state            True
state/region    False
ages            False
year            False
population       True
dtype: bool

#方式2：
abb_pop.info()

<class 'pandas.core.frame.DataFrame'>
Int64Index: 2544 entries, 0 to 2543
Data columns (total 5 columns):
state           2448 non-null object
state/region    2544 non-null object
ages            2544 non-null object
year            2544 non-null int64
population      2524 non-null float64
dtypes: float64(1), int64(1), object(3)
memory usage: 119.2+ KB

#找到有哪些state/region使得state的值为NaN，进行去重操作(将state中的空值对应的简称找到，且对简称进行去重)
abb_pop.head()

	state	state/region	ages	year	population
0	Alabama	AL	under18	2012	1117489.0
1	Alabama	AL	total	2012	4817528.0
2	Alabama	AL	under18	2010	1130966.0
3	Alabama	AL	total	2010	4785570.0
4	Alabama	AL	under18	2011	1125763.0

#思路：可以将state这一列中的空值对应的行数据取出，从该行数据中就可以取出简称的值

#1.将state中的空值定位到
abb_pop['state'].isnull()
#2.将上述的布尔值作为源数据的行索引
abb_pop.loc[abb_pop['state'].isnull()]#将state中空对应的行数据取出
#3.将简称取出
abb_pop.loc[abb_pop['state'].isnull()]['state/region']
#4.对简称去重
abb_pop.loc[abb_pop['state'].isnull()]['state/region'].unique()

#结论：只有PR和USA对应的全称数据为空值

array([], dtype=object)

#为找到的这些state/region的state项补上正确的值，从而去除掉state这一列的所有NaN
#思考：填充该需求中的空值可不可以使用fillna？
    # - 不可以。fillna可以使用空的紧邻值做填充。fillna(value='xxx')使用指定的值填充空值
    # 使用给元素赋值的方式进行填充！

#1.先给USA的全称对应的空值进行批量赋值

#1.1将USA对应的行数据找出（行数据中就存在state的空值）
abb_pop['state/region'] == 'USA'
abb_pop.loc[abb_pop['state/region'] == 'USA']#将usa对应的行数据取出

	state	state/region	ages	year	population
2496	NaN	USA	under18	1990	64218512.0
2497	NaN	USA	total	1990	249622814.0
2498	NaN	USA	total	1991	252980942.0
2499	NaN	USA	under18	1991	65313018.0
2500	NaN	USA	under18	1992	66509177.0
2501	NaN	USA	total	1992	256514231.0
2502	NaN	USA	total	1993	259918595.0
2503	NaN	USA	under18	1993	67594938.0
2504	NaN	USA	under18	1994	68640936.0
2505	NaN	USA	total	1994	263125826.0
2506	NaN	USA	under18	1995	69473140.0
2507	NaN	USA	under18	1996	70233512.0
2508	NaN	USA	total	1995	266278403.0
2509	NaN	USA	total	1996	269394291.0
2510	NaN	USA	total	1997	272646932.0
2511	NaN	USA	under18	1997	70920738.0
2512	NaN	USA	under18	1998	71431406.0
2513	NaN	USA	total	1998	275854116.0
2514	NaN	USA	under18	1999	71946051.0
2515	NaN	USA	total	2000	282162411.0
2516	NaN	USA	under18	2000	72376189.0
2517	NaN	USA	total	1999	279040181.0
2518	NaN	USA	total	2001	284968955.0
2519	NaN	USA	under18	2001	72671175.0
2520	NaN	USA	total	2002	287625193.0
2521	NaN	USA	under18	2002	72936457.0
2522	NaN	USA	total	2003	290107933.0
2523	NaN	USA	under18	2003	73100758.0
2524	NaN	USA	total	2004	292805298.0
2525	NaN	USA	under18	2004	73297735.0
2526	NaN	USA	total	2005	295516599.0
2527	NaN	USA	under18	2005	73523669.0
2528	NaN	USA	total	2006	298379912.0
2529	NaN	USA	under18	2006	73757714.0
2530	NaN	USA	total	2007	301231207.0
2531	NaN	USA	under18	2007	74019405.0
2532	NaN	USA	total	2008	304093966.0
2533	NaN	USA	under18	2008	74104602.0
2534	NaN	USA	under18	2013	73585872.0
2535	NaN	USA	total	2013	316128839.0
2536	NaN	USA	total	2009	306771529.0
2537	NaN	USA	under18	2009	74134167.0
2538	NaN	USA	under18	2010	74119556.0
2539	NaN	USA	total	2010	309326295.0
2540	NaN	USA	under18	2011	73902222.0
2541	NaN	USA	total	2011	311582564.0
2542	NaN	USA	under18	2012	73708179.0
2543	NaN	USA	total	2012	313873685.0

#1.2将USA对应的全称空对应的行索引取出
indexs = abb_pop.loc[abb_pop['state/region'] == 'USA'].index

abb_pop.iloc[indexs]
abb_pop.loc[indexs,'state'] = 'United States'

#2.可以将PR的全称进行赋值
abb_pop['state/region'] == 'PR'
abb_pop.loc[abb_pop['state/region'] == 'PR'] #PR对应的行数据
indexs = abb_pop.loc[abb_pop['state/region'] == 'PR'].index

abb_pop.loc[indexs,'state'] = 'PPPRRR'

#合并各州面积数据areas
abb_pop_area = pd.merge(abb_pop,area,how='outer')

#我们会发现area(sq.mi)这一列有缺失数据，找出是哪些行
abb_pop_area['area (sq. mi)'].isnull()
abb_pop_area.loc[abb_pop_area['area (sq. mi)'].isnull()] #空对应的行数据
indexs = abb_pop_area.loc[abb_pop_area['area (sq. mi)'].isnull()].index

#去除含有缺失数据的行
abb_pop_area.drop(labels=indexs,axis=0,inplace=True)

#找出2010年的全民人口数据(基于df做条件查询)
abb_pop_area.query('ages == "total" & year == 2010')

	state	state/region	ages	year	population	area (sq. mi)
3	Alabama	AL	total	2010.0	4785570.0	52423.0
91	Alaska	AK	total	2010.0	713868.0	656425.0
101	Arizona	AZ	total	2010.0	6408790.0	114006.0
189	Arkansas	AR	total	2010.0	2922280.0	53182.0
197	California	CA	total	2010.0	37333601.0	163707.0
283	Colorado	CO	total	2010.0	5048196.0	104100.0
293	Connecticut	CT	total	2010.0	3579210.0	5544.0
379	Delaware	DE	total	2010.0	899711.0	1954.0
389	District of Columbia	DC	total	2010.0	605125.0	68.0
475	Florida	FL	total	2010.0	18846054.0	65758.0
485	Georgia	GA	total	2010.0	9713248.0	59441.0
570	Hawaii	HI	total	2010.0	1363731.0	10932.0
581	Idaho	ID	total	2010.0	1570718.0	83574.0
666	Illinois	IL	total	2010.0	12839695.0	57918.0
677	Indiana	IN	total	2010.0	6489965.0	36420.0
762	Iowa	IA	total	2010.0	3050314.0	56276.0
773	Kansas	KS	total	2010.0	2858910.0	82282.0
858	Kentucky	KY	total	2010.0	4347698.0	40411.0
869	Louisiana	LA	total	2010.0	4545392.0	51843.0
954	Maine	ME	total	2010.0	1327366.0	35387.0
965	Montana	MT	total	2010.0	990527.0	147046.0
1050	Nebraska	NE	total	2010.0	1829838.0	77358.0
1061	Nevada	NV	total	2010.0	2703230.0	110567.0
1146	New Hampshire	NH	total	2010.0	1316614.0	9351.0
1157	New Jersey	NJ	total	2010.0	8802707.0	8722.0
1242	New Mexico	NM	total	2010.0	2064982.0	121593.0
1253	New York	NY	total	2010.0	19398228.0	54475.0
1338	North Carolina	NC	total	2010.0	9559533.0	53821.0
1349	North Dakota	ND	total	2010.0	674344.0	70704.0
1434	Ohio	OH	total	2010.0	11545435.0	44828.0
1445	Oklahoma	OK	total	2010.0	3759263.0	69903.0
1530	Oregon	OR	total	2010.0	3837208.0	98386.0
1541	Maryland	MD	total	2010.0	5787193.0	12407.0
1626	Massachusetts	MA	total	2010.0	6563263.0	10555.0
1637	Michigan	MI	total	2010.0	9876149.0	96810.0
1722	Minnesota	MN	total	2010.0	5310337.0	86943.0
1733	Mississippi	MS	total	2010.0	2970047.0	48434.0
1818	Missouri	MO	total	2010.0	5996063.0	69709.0
1829	Pennsylvania	PA	total	2010.0	12710472.0	46058.0
1914	Rhode Island	RI	total	2010.0	1052669.0	1545.0
1925	South Carolina	SC	total	2010.0	4636361.0	32007.0
2010	South Dakota	SD	total	2010.0	816211.0	77121.0
2021	Tennessee	TN	total	2010.0	6356683.0	42146.0
2106	Texas	TX	total	2010.0	25245178.0	268601.0
2117	Utah	UT	total	2010.0	2774424.0	84904.0
2202	Vermont	VT	total	2010.0	625793.0	9615.0
2213	Virginia	VA	total	2010.0	8024417.0	42769.0
2298	Washington	WA	total	2010.0	6742256.0	71303.0
2309	West Virginia	WV	total	2010.0	1854146.0	24231.0
2394	Wisconsin	WI	total	2010.0	5689060.0	65503.0
2405	Wyoming	WY	total	2010.0	564222.0	97818.0

#计算各州的人口密度(人口除以面积)
abb_pop_area['midu'] = abb_pop_area['population'] / abb_pop_area['area (sq. mi)']
abb_pop_area

	state	state/region	ages	year	population	area (sq. mi)	midu
0	Alabama	AL	under18	2012.0	1117489.0	52423.0	21.316769
1	Alabama	AL	total	2012.0	4817528.0	52423.0	91.897221
2	Alabama	AL	under18	2010.0	1130966.0	52423.0	21.573851
3	Alabama	AL	total	2010.0	4785570.0	52423.0	91.287603
4	Alabama	AL	under18	2011.0	1125763.0	52423.0	21.474601
5	Alabama	AL	total	2011.0	4801627.0	52423.0	91.593900
6	Alabama	AL	total	2009.0	4757938.0	52423.0	90.760506
7	Alabama	AL	under18	2009.0	1134192.0	52423.0	21.635389
8	Alabama	AL	under18	2013.0	1111481.0	52423.0	21.202163
9	Alabama	AL	total	2013.0	4833722.0	52423.0	92.206131
10	Alabama	AL	total	2007.0	4672840.0	52423.0	89.137211
11	Alabama	AL	under18	2007.0	1132296.0	52423.0	21.599222
12	Alabama	AL	total	2008.0	4718206.0	52423.0	90.002594
13	Alabama	AL	under18	2008.0	1134927.0	52423.0	21.649410
14	Alabama	AL	total	2005.0	4569805.0	52423.0	87.171757
15	Alabama	AL	under18	2005.0	1117229.0	52423.0	21.311810
16	Alabama	AL	total	2006.0	4628981.0	52423.0	88.300574
17	Alabama	AL	under18	2006.0	1126798.0	52423.0	21.494344
18	Alabama	AL	total	2004.0	4530729.0	52423.0	86.426359
19	Alabama	AL	under18	2004.0	1113662.0	52423.0	21.243767
20	Alabama	AL	total	2003.0	4503491.0	52423.0	85.906778
21	Alabama	AL	under18	2003.0	1113083.0	52423.0	21.232722
22	Alabama	AL	total	2001.0	4467634.0	52423.0	85.222784
23	Alabama	AL	under18	2001.0	1120409.0	52423.0	21.372470
24	Alabama	AL	total	2002.0	4480089.0	52423.0	85.460370
25	Alabama	AL	under18	2002.0	1116590.0	52423.0	21.299620
26	Alabama	AL	under18	1999.0	1121287.0	52423.0	21.389218
27	Alabama	AL	total	1999.0	4430141.0	52423.0	84.507583
28	Alabama	AL	total	2000.0	4452173.0	52423.0	84.927856
29	Alabama	AL	under18	2000.0	1122273.0	52423.0	21.408027
...	...	...	...	...	...	...	...
2419	Wyoming	WY	under18	2003.0	124182.0	97818.0	1.269521
2420	Wyoming	WY	total	2004.0	509106.0	97818.0	5.204625
2421	Wyoming	WY	under18	2004.0	123974.0	97818.0	1.267395
2422	Wyoming	WY	total	2002.0	500017.0	97818.0	5.111707
2423	Wyoming	WY	under18	2002.0	125495.0	97818.0	1.282944
2424	Wyoming	WY	total	2001.0	494657.0	97818.0	5.056912
2425	Wyoming	WY	under18	2001.0	126212.0	97818.0	1.290274
2426	Wyoming	WY	total	2000.0	494300.0	97818.0	5.053262
2427	Wyoming	WY	under18	2000.0	128774.0	97818.0	1.316465
2428	Wyoming	WY	total	1999.0	491780.0	97818.0	5.027500
2429	Wyoming	WY	under18	1999.0	130793.0	97818.0	1.337106
2430	Wyoming	WY	total	1997.0	489452.0	97818.0	5.003701
2431	Wyoming	WY	under18	1997.0	134328.0	97818.0	1.373244
2432	Wyoming	WY	under18	1998.0	132602.0	97818.0	1.355599
2433	Wyoming	WY	total	1998.0	490787.0	97818.0	5.017349
2434	Wyoming	WY	under18	1996.0	135698.0	97818.0	1.387250
2435	Wyoming	WY	total	1996.0	488167.0	97818.0	4.990564
2436	Wyoming	WY	total	1995.0	485160.0	97818.0	4.959823
2437	Wyoming	WY	under18	1995.0	136785.0	97818.0	1.398362
2438	Wyoming	WY	under18	1994.0	137733.0	97818.0	1.408054
2439	Wyoming	WY	total	1994.0	480283.0	97818.0	4.909965
2440	Wyoming	WY	under18	1992.0	137308.0	97818.0	1.403709
2441	Wyoming	WY	total	1992.0	466251.0	97818.0	4.766515
2442	Wyoming	WY	total	1993.0	473081.0	97818.0	4.836339
2443	Wyoming	WY	under18	1993.0	137458.0	97818.0	1.405242
2444	Wyoming	WY	total	1991.0	459260.0	97818.0	4.695046
2445	Wyoming	WY	under18	1991.0	136720.0	97818.0	1.397698
2446	Wyoming	WY	under18	1990.0	136078.0	97818.0	1.391135
2447	Wyoming	WY	total	1990.0	453690.0	97818.0	4.638103
2544	Puerto Rico	NaN	NaN	NaN	NaN	3515.0	NaN

2449 rows × 7 columns

#排序，并找出人口密度最高的州
abb_pop_area.sort_values(by='midu',axis=0,ascending=False).iloc[0]['state']

'District of Columbia'

标签：USA,under18,NaN,人口,案例,state,2010.0,total,pandas
来源： https://www.cnblogs.com/huahuawang/p/14889004.html