【刷题】牛客网——Rational Arithmetic (20)
作者:互联网
For two rational numbers, your task is to implement the basic arithmetics, that is, to calculate their sum, difference, product and quotient.
输入描述
每个输入文件包含一个测试用例,它在一行中给出了格式为“a1/b1 a2/b2”的两个有理数。
分子和分母都在long int的范围内。如果有负号,它必须只出现在分子前面。分母保证是非零数。
输出描述
对于每个测试用例,分别在4行中打印两个有理数的和、差、积和商。
每一行的格式是“number1操作符number2 = result”。注意所有有理数都必须是最简形式“k a/b”,其中k是整数部分,而a/b是最简分数部分。
如果数字是负数,它必须包含在一对括号中。
如果分母中除法为零,输出“Inf”作为结果。它保证所有输出整数都在long int的范围内。
#include <iostream>
#include <cmath>
using namespace std;
// 结构体表示分数
struct fraction
{
long long up;
long long down;
};
// 求最大公约数
long long gcd(long long a, long long b)
{
if(b == 0)
return a;
else
return gcd(b, a % b);
}
// 将结果化简为题目要求的形式
fraction reduction(fraction result)
{
// 分母为负,将符号转移给分子
if(result.down < 0)
{
result.up = -result.up;
result.down = -result.down;
}
if(result.up == 0)
result.down = 1;
else
{
// 约分
long long d = gcd(abs(result.up), abs(result.down));
result.up /= d;
result.down /= d;
}
return result;
}
// 分数加法运算
fraction add(fraction a, fraction b)
{
fraction result;
result.up = a.up * b.down + b.up * a.down;
result.down = a.down * b.down;
return result;
}
// 分数减法运算
fraction minu(fraction a, fraction b)
{
fraction result;
result.up = a.up * b.down - b.up * a.down;
result.down = a.down * b.down;
return result;
}
// 分数乘法运算
fraction multi(fraction a, fraction b)
{
fraction result;
result.up = a.up * b.up;
result.down = a.down * b.down;
return result;
}
// 分数除法运算
fraction divide(fraction a, fraction b)
{
fraction result;
result.up = a.up * b.down;
result.down = a.down * b.up;
return result;
}
// 打印数字
void printresult(fraction a)
{
a = reduction(a);
// 负号需要带括号
if(a.up < 0)
cout << "(";
// 整数
if(a.down == 1)
cout << a.up;
// 假分数
else if(abs(a.up) > a.down)
cout << a.up / a.down << " " << abs(a.up) % a.down << "/" << a.down;
// 真分数
else
cout << a.up << "/" << a.down;
if(a.up < 0)
cout << ")";
}
int main()
{
fraction a, b;
scanf("%lld/%lld %lld/%lld", &a.up, &a.down, &b.up, &b.down);
printresult(a); cout << " + "; printresult(b); cout << " = "; printresult(add(a, b)); cout << endl;
printresult(a); cout << " - "; printresult(b); cout << " = "; printresult(minu(a, b)); cout << endl;
printresult(a); cout << " * "; printresult(b); cout << " = "; printresult(multi(a, b)); cout << endl;
printresult(a); cout << " / "; printresult(b); cout << " = ";
if(b.up == 0)
cout << "Inf" << '\n';
else
{
printresult(divide(a,b));
cout << endl;
}
return 0;
}
标签:20,up,long,down,牛客,result,fraction,return,Arithmetic 来源: https://blog.csdn.net/m0_46613023/article/details/117593028