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linux shell中输出0-100中连续5个数字中的最小值、最大值、求和

作者:互联网

 

1、

root@PC1:/home/test2# ls     
test.sh
root@PC1:/home/test2# cat test.sh       ## script
#!/bin/bash
SUM=0
MIN=100
MAX=0
COUNT=0

while [ $COUNT -lt 5 ]
do
read -p "please input an integer of range 1-100: " INT
if [[ ! $INT =~ ^[0-9]+$ ]]
then
        echo "error! please input integer : "
        continue
elif [ $INT -gt 100 ] || [ $INT -lt 0 ]
then
        echo "error! please input integer 0-100: "
        continue
fi
let SUM=SUM+INT
[ $INT -le $MIN ] && MIN=$INT
[ $INT -ge $MAX ] && MAX=$INT
let COUNT++
done

echo "sum: $SUM"
echo "min: $MIN"
echo "max: $MAX"
root@PC1:/home/test2# bash test.sh       ## 执行脚本
please input an integer of range 1-100: 40
please input an integer of range 1-100: abc
error! please input integer :
please input an integer of range 1-100: 20
please input an integer of range 1-100: 588
error! please input integer 0-100:
please input an integer of range 1-100: 0
please input an integer of range 1-100: 32
please input an integer of range 1-100: r3
error! please input integer :
please input an integer of range 1-100: 70
sum: 162                           ## 结果输出
min: 0
max: 70

 

标签:shell,INT,linux,please,range,integer,input,100
来源: https://www.cnblogs.com/liujiaxin2018/p/16302782.html