转:SQL Server:获取当前日期是本月的第几周
作者:互联网
来源:https://blog.csdn.net/wjiaoling136/article/details/84911215
第一种:
--获取当前日期是本月的第几周 --测试:select dbo.getMonthWeek(getdate()) 结果:10月的第2周 CREATE function [dbo].[getMonthWeek](@d datetime) returns varchar(20) as begin declare @returns varchar(20), @monthfirstDay datetime, @firstMondy datetime select @monthfirstDay=left(convert(varchar,@d,23),7)+'-01' if not exists(select 1 from master.dbo.spt_values where type=N'P' and number between 0 and datediff(d,@monthfirstDay,@d) and datepart(dw,dateadd(d,number,@monthfirstDay))=2) begin select @monthfirstDay=dateadd(mm,-1,@monthfirstDay) end ;with t as(select 'days'=dateadd(d,number,@monthfirstDay) from master.dbo.spt_values where type=N'P' and number<=7) select @firstMondy=min([days]) from t where datepart(dw,[days])=2 select @returns=rtrim(datepart(mm,@monthfirstDay))+'月的第'+rtrim(datediff(d,@firstMondy,@d)/7+1)+'周' return @returns end
第二种:
--获取当前日期是本月的第几周 --测试:select dbo.WeekOfMonth(getDate());结果:2 CREATE FUNCTION [dbo].[WeekOfMonth](@day datetime) RETURNS int AS begin ----declare @day datetime declare @num int declare @Start datetime declare @dd int declare @dayofweek char(8) declare @dayofweek_num char(8) declare @startWeekDays int ---set @day='2009-07-05' if datepart(dd,@day)=1 return 1 else set @Start= (SELECT DATEADD(mm, DATEDIFF(mm,0,@day), 0)) --一个月第一天的 set @dayofweek= (datename(weekday,@Start)) ---得到本月第一天是周几 set @dayofweek_num=(select (case @dayofweek when '星期一' then 2 when '星期二' then 3 when '星期三' then 4 when '星期四' then 5 when '星期五' then 6 when '星期六' then 7 when '星期日' then 1 end)) set @dayofweek_num= 7-@dayofweek_num+1 ---得到本月的第一周一共有几天 ---print @dayofweek_num set @dd=datepart(dd,@day) ----得到今天是这个月的第几天 --print @dd if @dd<=@dayofweek_num --小于前一周的天数 return 1 else set @dd=@dd-@dayofweek_num if @dd % 7=0 begin set @num=@dd / 7 return @num+1 end else --if @dd % 7<>0 set @num=@dd / 7 set @num=@num+1+1 return @num end
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原文链接:https://blog.csdn.net/wjiaoling136/article/details/84911215
标签:dayofweek,set,几周,Server,num,SQL,monthfirstDay,declare,select 来源: https://www.cnblogs.com/zouhao/p/12570296.html