mysql多对多搜索

我有下表

CREATE TABLE IF NOT EXISTS `user` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `name` varchar(100) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8  ;


CREATE TABLE IF NOT EXISTS `skill` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `name` varchar(100) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8  ;

CREATE TABLE IF NOT EXISTS `user_skill` (
  `user_id` int(11) NOT NULL,
  `skill_id` int(11) NOT NULL ,
  PRIMARY KEY (`user_id`,`skill_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8  ;

表user_skill充当多对多表.现在,我想选择所有具有skill_ids至少1&的用户. 2.如何在mysql中做到这一点

解决方法:

select u.id, u.name
from `user` u
inner join `user_skill` us on u.id = us.user_id
where us.skill_id in (1, 2)
group by u.id
having count(distinct us.skill_id) = 2

标签：many-to-many,mysql
来源： https://codeday.me/bug/20191127/2075787.html