SAS--sql2
作者：互联网
libname clinic 'E:\sas';
data admit;
set sasuser.admit;
run;
proc sql;
select name, sex , age, height
from sasuser.admit
where (actlevel='LOW' and height>70) or age>35
order by sex desc ,height asc; /*排序*/
quit;
/*删除增加行*/
proc sql;
delete from admit
where date=1;
quit;
proc sql;
alter atble admit
drop date;
quit;
proc sql;
alter table admit
add date num format=date9.,hh num format=comma10.2,xx char(3);
quit;
proc sql;
alter table admit
modify xx char(20) label='xxxx';
quit;
/*选择部分观测*/
proc sql;
select * from admit(firstobs=2 obs=10);
quit;
proc sql outobs=10; /*inobs=10 对前10行进行操作*/
select * from admit;
quit;
/********文本查询************/
proc sql number;
select * from admit
where name like 'P%'; /*name以P开头*/
quit;
proc sql;
select * from admit
where name like '%W';
quit;
proc sql;
select * from admit
where name not like '%ing%';
quit;
proc sql;
select * from admit
where name like '_ing, E'; /*引号里的内容必须完全===变量内容*/
quit;
proc sql;
select * from admit
where Name is missing;
quit;
proc sql;
select * from sasuser.acities
where name contains 'International'; *变量name中contains Internationl 子字符串的观察单位,查询;
run;
proc sql;
select * from admit
where age between 30 and 50;
quit;
proc sql;
select *from admit
where name =*'smith'; /*模糊匹配，可以搜出smythe*/
quit;
data admitt;
set sasuser.admit;
if index(name,'ing')>0;
run;
proc print data=admitt;
run;
/*计算式条件查询（子查询）*/
proc sql;
select actlevel, avg(height) as hh
from admit
group by actlevel
having avg(height) > (select avg(height) from admit); /***************/
quit;
/*any all 注意逻辑*/
proc sql;
select name,height
from admit
where height = any(select height from sasuser.admitjune where sex="M"); /*admit中height大于任何一个admitJune女生身高*/
quit;
proc sql;
select *
from admit
where exists (select * from sasuser.added where i=6); /*只要brackets里面执行结果不为null，则外面的sql执行*/
quit;
/*except去重*/
proc sql;
select name,maxhr
from sasuser.stress98 /*98中去掉98a中出现的名字*/
except
select name
from sasuser.stress98a;
quit;
proc sql;
select name, maxhr /*重复的名字不去掉*/
from sasuser.stress98
except ALL
select name
from sasuser.stress98a;
quit;
/*保留所有重复的列和行*/
proc sql;
select *
from sasuser.stress98
except corr
select *
from sasuser.stress98a;
quit;
/*intersect查重*/
proc sql;
select name
from sasuser.stress98
intersect /*选出98中98a出现的名字*/
select name
from sasuser.stress98a;
quit;
proc sql;
select *
from sasuser.stress98
except corr
select *
from sasuser.stress98a;
quit;
/*union / outer union*/
/*创建空表*/
proc Sql; /*自定义的*/
create table datt
(name char(30), sex char(2), age num ,begin num format date9. label ='begin timing');
quit;
proc sql; /*用某个表的列名称和格式*/
create table stresss
like sasuser.stress98;
quit;
proc sql outobs=0;
create table sass as
select *
from sasuser.stress98;
quit;
/*逻辑核查（建库）*/
proc Sql;
create table datt
(name char(30), sex char(2), age num ,begin num format date9. label ='begin timing',
height num,
constraint height check (height le 3)); /*height值不能大于3*/
quit;
proc sql;
insert into datt
set height=3.01; /*会报错*/
quit;
/*插入一行观测*/
proc sql;
insert into admit (name,age) values ( 'yangbo',25);
quit;
proc sql ;
insert into admit values ('1234' ,'wt','F',26,1,155,45,'HH',22.2);
quit;
proc sql;
insert into admit
set
name='xx',
age=8;
quit;
/*更新data*/
proc sql;
update admit set height=1.55,sex='n'
where name='wt';
quit;
/*验证语法正确*/
proc sql;
validate
select name, BMI
from admit;
quit;
proc sql noexec;
select name, BMI
from admit;
quit;
/*计算已有变量创建新变量*/
proc sql;
select name , height*height/weight as BMI
from admit
where calculated BMI > 30; /*note clause calculated*/
quit;
/*查询列*/
proc sql feedback noprint; /*check log*/
select * from admit;
quit;
/*label format*/
proc sql;
select name lable="xxx" , fee format=dollar12.2
from admit;
quit;
/*常用统计描述*/
/*一列求和，纵向*/
proc sql;
select sum(height),name /*第一列均为height之和,且无变量名*/
from admit;
quit;
/*多列求和，横向*/
proc sql;
select name , sum(fee,height) as aa
from admit;
quit;
/*按组*/
proc sql;
select sum(height),name /*第一列均为height之和,且无变量名*/
from admit
group by sex;
quit;
/*计数*/
proc sql;
select distinct (actlevel) as level ,count(*) as count
from admit
group by actlevel;
quit;
/*distinct查看取唯一值*/
proc sql;
select distinct (actlevel) as level
from admit
quit;
proc sql;
select actlevel ,avg(height) as H
from sasuser.admit
group by actlevel;
quit;
/**************拼表**************/
/*内连接*/
data sasuser.stress98a;
set sasuser.stress98;
where maxhr >170 and maxhr < 190;
keep name year hr; /*单独修改了一个name，Disco, 6*/
hr+maxhr; /*添加一列*/
run;
proc sql;
create table nnnerj as /*创建表和直接显示结果不一样，创建表中没有重复显示变量*/
select *
from sasuser.stress98 join sasuser.stress98a
on stress98.name=stress98a.name; /*相当于98a中有部分98中的人，且a有这部分人其他变量，最后拼出来：共有的人、所有变量*/
quit;
/*左外拼*/
proc sql;
create table leftout as /*左表不动，添加右表中能在左表用得到的信息*/
select *
from sasuser.stress98 left join sasuser.stress98a
on stress98.name=stress98a.name;
quit;
/*右外拼*/
proc sql;
create table rightout as /******有一个问题******/ /*在创建表时，省去了重复变量，但是没右表独有的值没显示（重复变量中）*/
select *
from sasuser.stress98 right join sasuser.stress98a
on stress98.name=stress98a.name;
quit;
/*全连接*/
proc sql;
select *
from sasuser.stress98 full join sasuser.stress98a
on stress98.name=stress98a.name;
quit;
/*笛卡尔积*/
proc sql;
select *
from sasuser.stress98 cross join sasuser.stress98a;
quit;
/*创建视图*/
proc sql;
create view vadmit as
select *
from admit;
quit;
/*条件赋值*/
proc sql;
select *,
(case when sex="M" then 1 else 2 end )as group
from admit;
quit;
标签：quit,name,sql2,admit,sql,SAS,proc,select 来源： https://www.cnblogs.com/super-yb/p/11882073.html