如何在PHP CodeIgniter中将日期作为参数传递给MySQL存储过程?
作者:互联网
我正在尝试在我的Web应用程序中创建日期范围过滤.为此,我使用日期选择器进行输入,并将其传递给控制器进行建模.当我回显它时,它将为我提供从日期选择器中选择的正确日期值.但是,当我运行我的代码时,它给了我空白的输出.我想知道我的代码有什么问题.
这是我的SP代码:
DELIMITER $$
CREATE DEFINER=`root`@`localhost` PROCEDURE `testDefects`(IN `startdate` DATE, IN `enddate` DATE)
NO SQL
DETERMINISTIC
BEGIN
SELECT `defect_id`, `user_id`, `defect_rooms`, `defect_start_date`, `defect_subject`, `defect_responsibility`, `defect_time_frame`, `defect_followup_date`, `defect_assign_to`, `defect_notes`, `defect_details`, `defect_status`, `defect_updated_date` FROM `tbl_defects` WHERE defect_followup_date BETWEEN startdate AND enddate;
END$$
DELIMITER ;
这是我的控制器代码:
public function DefectFilterTest()
{
# code...
$user = $this->ion_auth->user()->row();
$data['username'] = $user->username;
$data['user_id'] = $user->id;
$user_id = $user->id;
$data['groupId'] = $this->l->groupId($user_id);
$data['group'] = $data['groupId']['0']->group_id;
$data['title'] = 'Property Defects List';
$startdate = $this->input->post('fromdate');
$enddate = $this->input->post('todate');
if($startdate == ''){
$startdate ='1900-01-01';
}
if($enddate == ''){
$enddate ='2100-01-01';
}
echo $startdate. "<br>";
echo $enddate. "<br>";
$data['defectslist'] = $this->p->testDefects($startdate, $enddate);
echo "<pre>";
print_r($data['defectslist']);
echo "</pre>";
exit();
$this->load->view('template/header', $data);
$this->load->view('Property/defectList', $data);
$this->load->view('template/footer');
}
这是我的模型代码:
public function testDefects($startdate, $enddate)
{
# code... testDefects
$query = $this->db->query("call testDefects($startdate, $enddate)");
if ($query->num_rows()) {
$data = $query->result();
$query->next_result();
$query->free_result();
return $data;
}else{
return false;
}
}
我已经用谷歌搜索出来了,但是我被困住了,欢迎任何帮助,谢谢.
解决方法:
尝试这个:
# code... testDefects
$query = $this->db->query("call testDefects('$startdate', '$enddate')");
标签:codeigniter-3,parameters,mysql,php,stored-procedures 来源: https://codeday.me/bug/20191109/2012760.html