在SQL / MySQL中,当没有主ID索引时,可以使用左外部联接来查找重复项吗?
作者:互联网
我想尝试使用外部联接找出表中的重复项:
如果表具有主索引ID,则以下外部联接可以找出重复的名称:
mysql> select * from gifts;
+--------+------------+-----------------+---------------------+
| giftID | name | filename | effectiveTime |
+--------+------------+-----------------+---------------------+
| 2 | teddy bear | bear.jpg | 2010-04-24 04:36:03 |
| 3 | coffee | coffee123.jpg | 2010-04-24 05:10:43 |
| 6 | beer | beer_glass.png | 2010-04-24 05:18:12 |
| 10 | heart | heart_shape.jpg | 2010-04-24 05:11:29 |
| 11 | ice tea | icetea.jpg | 2010-04-24 05:19:53 |
| 12 | cash | cash.png | 2010-04-24 05:27:44 |
| 13 | chocolate | choco.jpg | 2010-04-25 04:04:31 |
| 14 | coffee | latte.jpg | 2010-04-27 05:49:52 |
| 15 | coffee | espresso.jpg | 2010-04-27 06:03:03 |
+--------+------------+-----------------+---------------------+
9 rows in set (0.00 sec)
mysql> select * from gifts g1 LEFT JOIN (select * from gifts group by name) g2
on g1.giftID = g2.giftID where g2.giftID IS NULL;
+--------+--------+--------------+---------------------+--------+------+----------+---------------+
| giftID | name | filename | effectiveTime | giftID | name | filename | effectiveTime |
+--------+--------+--------------+---------------------+--------+------+----------+---------------+
| 14 | coffee | latte.jpg | 2010-04-27 05:49:52 | NULL | NULL | NULL | NULL |
| 15 | coffee | espresso.jpg | 2010-04-27 06:03:03 | NULL | NULL | NULL | NULL |
+--------+--------+--------------+---------------------+--------+------+----------+---------------+
2 rows in set (0.00 sec)
但是,如果表没有主索引ID,那么仍然可以使用外部联接来查找重复项吗?
附言也感谢任何非外部联接解决方案.如果可能,我想检查在没有主ID索引的情况下是否可以使用外部联接来完成此操作.感谢您的帮助.
解决方法:
使用EXISTS子句:
SELECT *
FROM gifts go
WHERE EXISTS
(
SELECT NULL
FROM gifts gi
WHERE gi.name = go.name
LIMIT 1, 1
)
标签:outer-join,sql,mysql,duplicates 来源: https://codeday.me/bug/20191106/2000226.html