PHP-将空值设置为MySQL中没有的日期

因此,我正在使用该代码从MySQL中获取一些数据：

<?
$query=mysql_query("SELECT date,COUNT(*) as num FROM downloads WHERE prjID='".$_GET['id']."' GROUP BY date ORDER BY date ASC");
$num=mysql_num_rows($query);
$res='';
$i=0;
while($row=mysql_fetch_array($query)){

$i++;
$date=date("d.m.Y", strtotime($row['date']));

$dan=date("d", strtotime($row['date']));
$mesec=date("m", strtotime($row['date']));
$leto=date("Y", strtotime($row['date']));

if($i=1){
$danPrvi=$leto.", ".($mesec-1).", ".$dan;
$dan1=date("d", strtotime(time()));
$mesec1=date("m", strtotime(time()));
$leto1=date("Y", strtotime(time()));
$danZadnji=$leto1.", ".($mesec1-1).", ".$dan1;
}

$numb=1;

if($row['num']!=1){
$res.="[Date.UTC(".$leto.",".($mesec-1).",".$dan."),".$row['num']."], ";
}
else{
if($i!=$num){
$res.="[Date.UTC(".$leto.",".($mesec-1).",".$dan."),".$numb."], ";
}
else{
$res.="[Date.UTC(".$leto.",".($mesec-1).",".$dan."),".$numb."]";
}
}
}
?>

我得到这样的结果：

1.3.2013 - 1
6.3.2013 - 5

但我想得到这样的结果：

1.3.2013 - 1
2.3.2013 - 0
3.3.2013 - 0
4.3.2013 - 0
5.3.2013 - 0
6.3.2013 - 1

我也在使用Highcharts,因此日期值的格式必须类似于Date.UTC(year,month-1,day)

编辑：

我的数据库中没有所有日期.在我的例子中,只有1.3.2013和6.3.2013,那么我将如何为所有日期之间的所有不具有> = 1的值检测并设置0值？

解决方法:

我想您需要做的是建立一个结构来保存您感兴趣的日期,并在查询中使用它或对查询数据进行后处理.例如：

<?php
$query=mysql_query("SELECT date,COUNT(*) as num FROM downloads WHERE prjID='".$_GET['id']."' GROUP BY date ORDER BY date ASC");
$num=mysql_num_rows($query);

// Get the first and last dates in the result set
$firstRow = mysql_result($query, 0);
$lastRow = mysql_result($query, $num-1);

// Now make thos the begin and end dates
$beginDate = new DateTime(strtotime($firstRow['date']));
$endDate = new DateTime(strtotime($lastRow['date']));
$currentDate = $beginDate;
$interestingDates = array();

// Populate our interestingDates array with all counts set to 0
while ($currentDate <= $endDate){
    $interestingDates[$currentDate->format('d.m.Y')] = 0;
    $currentDate->add(new DateInterval('P1D'));
}

// Reset the data result for looping over
mysql_data_seek($query,0);
while($row=mysql_fetch_array($query)){
    // Go ahead and format the string
    $formatedString = date("d.m.Y", strtotime($row['date']));

    // If the string is in our interestingDates array, update the count
    if (array_key_exists($formatedString, $interestingDates)){
        $interestingDates[$formatedString] = $row['num'];
    }
}

// Print it out
foreach ($interestingDates as $key=>$value){
    print "$key - $value\n";
}

注1：从PHP 5.5.0开始不推荐使用mysql_query,将来将删除它.请使用其他API-我建议pdo_mysql.

注意2：当前查询未参数化.使用PDO,这可能看起来像：

$sth = $dbh->prepare('SELECT date,COUNT(*) as num FROM downloads WHERE prjID= :prjID GROUP BY date ORDER BY date ASC');
$sth->bindParam(':prjID', $_GET['id'], PDO::PARAM_INT);
$sth->execute();

免责声明-我实际上并没有运行此代码,只是将其写在脑海中.您可能需要对其进行测试/调试.

标签：date-formatting,mysql,php
来源： https://codeday.me/bug/20191031/1972926.html