php-如何将其保存在数据库中

在我的数据库中,我有ID,product_id,company_name,service,qty,delivery_cost,delivery_date,order_status等列.

我认为我使用了Jquery和HTML,jquery在单击添加更多按钮时动态添加了更多的product_id,service,delivery_cost,qty,delivery_date,order_status输入字段.在提交​​表单时,我在做dd($allData)时将其输入控制器

我的问题是如何将这些数据保存在数据库中

array:8 [▼
  "_token" => "gSddIeA11OBV60xU9YiDXn8fmsfkwxlQ85QmDdkQ"

  "service" => array:3 [▼
    0 => "cement"
    1 => "iron"
    2 => "steel"
  ]
  "qty" => array:3 [▼
    0 => "5"
    1 => "44"
    2 => "5"
  ]
  "delivery_cost" => array:3 [▼
    0 => "5465"
    1 => "553"
    2 => "554"
  ]
  "delivery_date" => array:3 [▼
    0 => "2016-12-16"
    1 => "2016-12-08"
    2 => "2016-12-17"
  ]
  "order_status" => "Confirm"
  "delivery_vehicle" => array:1 [▼
    0 => "Self_elivery"
   1 => "Self_elivery"
   2 => "Self_elivery"
  ]
]
public function store(Request $request)
    {
        $allData= $request->all();
        dd($allData);
         $product = new Order;


   }

我尝试这个

public function store(Request $request)
    {


        $date = $request->get('delivery_date');
        $cost = $request->get('delivery_cost');
        $service = $request->get('service');//add quotes next to service

        foreach($date as $deliveryDate)
        {
           foreach($cost as $proAmount){
            $db = new Order;
            $db->delivery_date = $deliveryDate;
            $db->amount = $proAmount;
            $db->save();

        }
}
        return"ok";
} 

我尝试过这种方式,但它多次存储相同的数据可能是由于循环内部的循环.我需要您的帮助才能将这些数据存储在数据库中

解决方法:

使用for()应该适合您：

$data = $request->all();

for ($i = 0; $i < count($data['delivery_date']); $i++) {
    $db = new Order;
    $db->delivery_date = $data['delivery_date'][$i];
    $db->delivery_cost = $data['delivery_cost'][$i];
    ....
    $db->save();
}

标签：laravel,php,jquery,database,laravel-5-3
来源： https://codeday.me/bug/20191026/1936441.html