php-如何使用sql数据填充html下拉列表
作者:互联网
我是PHP新手,希望能有所帮助.
我试图用我的SQL数据库中的数据填充HTML下拉列表.
我希望能够从下拉列表中选择一个项目,然后使用数据库中的相关记录来填充HTML表.
到目前为止,我已经设法连接到数据库并从相关表中检索所有数据.
有人可以帮我设置下拉列表中的内容吗?
谢谢
<?php
$username = 'root';
$password = '';
$conn = new PDO( 'mysql:host=localhost; dbname=Oaktown', $username, $password );
$sql ="SELECT RoundNumber, RoundDate, HomeTeam, HomeTeamScore, AwayTeam, AwayTeamScore FROM Fixture";
$statement = $conn->prepare( $sql );
$statement->execute();
$results = $statement->fetchAll( PDO::FETCH_ASSOC );
?>
<h2>Competitions</h2>
<article>
<p id="TableHeader1">Fixture Information</p>
<P>Select Round and Game number from the dropdown list under Round Number.</P>
<br>
<br><form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>">
<p id="TableHeader2">Round Number
<select style="width:250px"></select>  <input class="button"
type="submit" name="Get" value="Get Fixture Results"></p>
<p id="TableHeader2">Results</p>
<table class="table">
<tr><td><b>Round Number:</b></td>
<?php foreach( $results as $row ){
echo "<td>";
echo $row['RoundNumber'];
}
?>
</tr>
<tr>
<td><b>Round Date:</b></td>.
<?php foreach( $results as $row ){
echo "<td>";
echo $row['RoundDate'];
}
?>
</tr>
<tr>
<td><b>Home Team:</b></td>
<?php foreach( $results as $row ){
echo "<td>";
echo $row['HomeTeam'];
}
?>
</tr>
<tr>
<td><b>Home Team Score:</b></td>
<?php foreach( $results as $row ){
echo "<td>";
echo $row['HomeTeamScore'];
}
?>
</tr>
<tr>
<td><b>Away Team:</b></td>
<?php foreach( $results as $row ){
echo "<td>";
echo $row['AwayTeam'];
}
?>
</tr>
<tr>
<td><b>Away Team Score:</b></td>
<?php foreach( $results as $row ){
echo "<td>";
echo $row['AwayTeamScore'];
}
?>
<td colspan="2><?php echo $message; ?>"></td>
</tr>
</table>
</form>
解决方法:
使用类似的代码块(如用于表的代码块),您可以执行以下操作:
<select>
<?php foreach( $results as $row ){
echo "<option value='" . $row['value column'] . "'>" . $row['text column'] . "</option>";
}
?>
</select>
如果您没有或需要一对值,则只需执行以下操作:
<select>
<?php foreach( $results as $row ){
echo "<option>" . $row['text column'] . "</option>";
}
?>
</select>
标签:html-select,html,mysql,php 来源: https://codeday.me/bug/20191025/1927648.html